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malfutka [58]
3 years ago
5

If f(x) = -3x +4 and g(x) = 2, solve for the value of x forwhich (fx) = g(x) is true.​

Physics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

x=-\frac{2}{3}

Explanation:

Let:

f(x)=-3x+4\\\\And\\\\g(x)=2

We need to know for which value of x the function f(x) is equal to g(x):

f(x)=g(x)

Therefore, we need to solve for the previous equation for x:

Replacing the values of f(x) and g(x):

-3x+4=2

Subtract 4 from both sides:

-3x+4-4=2-4\\\\-3x=-2

Multiply both sides by -1

-3x(-1)=-2(-1)\\\\3x=2

Divide both sides by 3:

\frac{3x}{3} =\frac{2}{3} \\\\x=\frac{2}{3}

Therefore the value of x for which f(x)=g(x) is x=\frac{2}{3}.

Verify the result:

-3(\frac{2}{3} )+4=2\\\\-2+4=2\\\\2=2

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Answer:

y = 10.44cos(2t - 0.291) cm

Explanation:

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tanφ = -0.3

φ = -0.291 radians

10 = Acos(-0.291)

A = 10/cos(-0.291) = 10.44

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3 years ago
Explain the relationship between velocity and acceleration. Are these scalar or vector quantities?
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A boy throws a ball with an initial velocity of 19.6 m/s. What maximum height does the ball reach?
Wewaii [24]
<h2>Hello!</h2>

The answer is: 19.59 m

<h2>Why?</h2>

Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.

When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:

We will use the following formula:

Vf^2=Vi^2+2*g*s

Where:

Vf= Final velocity = 0

Vi= Initial velocity = \frac{19.6m}{s}

g = Gravity Acceleration = \frac{9.81m}{s^{2} }

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Have a nice day!

8 0
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Mary and her younger brother Alex decide to ride the 17-foot-diameter carousel at the State Fair. Mary sits on one of the horses
lorasvet [3.4K]

Answer:

\omege_A=\omega_M

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r = Distance from center

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\omega_A=\omega_M

Tangential speed speed is given by

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The tangential speed of Mary is v_M=1.6v_A

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