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malfutka [58]
3 years ago
5

If f(x) = -3x +4 and g(x) = 2, solve for the value of x forwhich (fx) = g(x) is true.​

Physics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

x=-\frac{2}{3}

Explanation:

Let:

f(x)=-3x+4\\\\And\\\\g(x)=2

We need to know for which value of x the function f(x) is equal to g(x):

f(x)=g(x)

Therefore, we need to solve for the previous equation for x:

Replacing the values of f(x) and g(x):

-3x+4=2

Subtract 4 from both sides:

-3x+4-4=2-4\\\\-3x=-2

Multiply both sides by -1

-3x(-1)=-2(-1)\\\\3x=2

Divide both sides by 3:

\frac{3x}{3} =\frac{2}{3} \\\\x=\frac{2}{3}

Therefore the value of x for which f(x)=g(x) is x=\frac{2}{3}.

Verify the result:

-3(\frac{2}{3} )+4=2\\\\-2+4=2\\\\2=2

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Answer:

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Hope it will help you :)❤

8 0
3 years ago
Two cars collide at an intersection. Car A , with a mass of 2000 kg, is going from west to east, while car B, of mass 1500 kg, i
devlian [24]

Answer:

The answer of the part (a) is v2 = 7.09 m/s

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Explanation of the both parts of answer  is in the following attachments

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3 years ago
Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note
love history [14]

Answer:

The energy is 9.4\times10^{-21}\ J

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

Q=\Delta U+W

Q=\Delta U+nRT

Put the value into the formula

4480=\Delta U+\dfrac{20}{28}\times8.314\times77

\Delta U=4480-\dfrac{20}{28}\times8.314\times77

\Delta U=4022.73\ J

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

N=n\times \text{Avogadro number}

Put the value into the formula

N=\dfrac{20}{28}\times6.02\times10^{23}

N=4.3\times10^{23}

We need to calculate the energy

Using formula of energy

E=\dfrac{\Delta U}{N}

Put the value into the formula

E=\dfrac{4022.73}{4.3\times10^{23}}

E=9.4\times10^{-21}\ J

Hence, The energy is 9.4\times10^{-21}\ J

4 0
3 years ago
8. What is the momentum of a 120-kg professional fullback running<br> across the line at 11.2 m/s?
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Answer:

134r kgm^-1 or 1344 kg /m

Explanation:

Momentum is is given by:

p=mv

Where:

p is momentum, m is mass in kg and v is velocity in ms−1

p=120kg×11.2 m/ s= 1344 kgms=1344kgm^−1

5 0
3 years ago
What is time machine ? Has it been invented it ? What is price of it??
stepan [7]

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