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BARSIC [14]
3 years ago
5

A model of a helicopter rotor has four blades, each of length 3.0 m from the central shaft to the blade tip. The model is rotate

d in a wind tunnel at a rotational speed of 560 rev/min.part A :What is the linear speed of the bladetip?part B :What is the radial acceleration of the bladetip expressed as a multiple of the acceleration of gravity,g?
Physics
1 answer:
ohaa [14]3 years ago
4 0

Answer with Explanation:

We are given that

r=3 m

Angular frequency=\omega=560rev/min

A.1 revolution=2\pi radian

560 revolutions=560\times 2\pi rad

Angular frequency=2\times 3.14\times \frac{560}{60}rad/s

1 min=60 s

\pi=3.14

Angular frequency=\omega=58.6rad/s

Linear speed=\omega r

Using the formula

Linear speed=58.6\times 3=175.8m/s

Hence, the linear speed of the blade tip=175.8m/s

B.Radial acceleration=a_{rad}=\frac{v^2}{r}

By using the formula

Radial acceleration=a_{rad}=\frac{(175.8)^2}{3}= 10.301\times 10^3m/s^2

Radial acceleration=\frac{10.301}{9.8}g\times 10^3=1.05\times 10^3 g

Where g=9.8m/s^2

Hence, the radial acceleration=1.05\times 10^3 g

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What is described by the terms body-centered cubic and face-centered cubic?
Montano1993 [528]
In physical chemistry, the terms body-centered cubic  (BCC) and face-centered cubic (FCC) refer to the cubic crystal system of a solid. Each solid is made up simple building blocks called lattice units. There are different layouts of a lattice unit.

It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.

7 0
3 years ago
A ball of mass 8 kg falls from rest from a height of 100 m. Neglecting air resistance,calculate its kinetic energy after falling
astra-53 [7]
As an object falls from rest, its gravitational energy is converted to kinetic energy

G.P.E = K.E = mgh

K.E = (80 Kg)(9.8 m/s²)(30 m)

K.E. = 23,520 J
4 0
4 years ago
Read 2 more answers
Which component measures the potential difference across a branch in a circuit? A.switch. B.resistor. C.ammeter. D.voltmeter.
Mademuasel [1]

Answer: The correct answer is option (D).

Explanation:

Voltmeter is a device which measures the the voltage applied across the circuit. It is an electrical instrument used to measure the electric potential between the two points in an electric circuit.

Where as:

A switch is the device which used to connect or disconnect the circuit.

Resistor is a device which opposes the flow of current is an electric circuit.

An ammeter the is an electrical device which measures the amount of current in flowing in amperes in an electrical circuit

Hence,the correct answer is option (D).

4 0
3 years ago
Read 2 more answers
The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at ????????,2=17.9vi,2=17.9
AleksAgata [21]

Answer:

V=27.24 m/s

Explanation:

We need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_{f}\\

The velocity of the eagle its defined by its two components:

v_x=V*cos(\theta)\\v_y=V*sin(\theta)\\v_x=35.9*cos(61.9^o)=16.9m/s\\v_y=35.9*sin(61.9^o)=31.7m/s

2*(16.9m/s(i)+31.66m/s(j))+17.9m/s(i)=3*v_f\\v_f=17.23m/s(i)+21.10m/s(j)

because speed is a scalar value:

V=\sqrt{(21.10m/s)^2+(17.23)^2}\\V=27.24m/s

6 0
4 years ago
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
kakasveta [241]

Answer:

W=4037.36\ J

Explanation:

Given:

mass of ice melted, m=3.3\times10^{-2}\ kg

time taken by the ice to melt, t=5\ min=300\ s

latent heat of the ice, L=3.34\times 10^5\ J

Now the heat rejected by the Carnot engine:

Q_R=m.L

Q_R=0.033\times 3.34\times 10^5

Q_R=11022\ J

Since we have boiling water as hot reservoir so:

T_H=373\ K

The cold reservoir is ice, so:

T_L=273\ K

Now the efficiency:

\eta=1-\frac{T_L}{T_H}

\eta=1-\frac{273}{373}

\eta=26.81\%

Now form the law of energy conservation:

Heat supplied:

Q_S-W=Q_R

where:

Q_S= heat supplied to the engine

Q_S-\eta\times Q_S=Q_R

Q_S(1-\eta)=Q_R

Q_S=\frac{11022}{1-0.2681}

Q_S=15059.36\ J

Now the work done:

W=Q_S-Q_R

W=15059.36-11022

W=4037.36\ J

8 0
3 years ago
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