A 64 kg cross-country skier glides over snow. Thecoefficient
1 answer:
Answer:
The distance traveled by the skier is 5.309 km
Solution:
As per the question:
Mass of the skier, m = 64 kg
Coefficient of friction between the ski and the snow,
Mass of snow, M = 5.0 kg
Now,
To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:
We know that:
where
= coefficient of friction
N = Normal Reaction
N = mg
Thus
(1)
Also,
(2)
where
= Latent Heat of fusion
Thus from eqn (1) and (2):
s = 5.309 km
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a) 1.57 m/s
The sock spins once every 2.0 seconds, so its period is
T = 2.0 s
Therefore, the angular velocity of the sock is
The linear speed of the sock is given by
where
is the angular velocity
r = 0.50 m is the radius of the circular path of the sock
Substituting, we find:
B) Faster
In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:
At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:
Therefore, the new linear speed would be:
And substituting,
So, we see that the linear speed has doubled.
Explanation:
(a) For an isothermal process, work done is represented as follows.
W =
Putting the given values into the above formula as follows.
W =
=
=
=
= 29596.78 J
or, = 29.596 kJ (as 1 kJ = 1000 J)
Therefore, the required work is 29.596 kJ.
(b) For an adiabatic process, work done is as follows.
W =
=
=
= 49.41 kJ
Therefore, work required to produce the same compression in an adiabatic process is 49.41 kJ.
(c) We know that for an isothermal process,
or,
=
= 11 atm
Hence, the required pressure is 11 atm.
(d) For adiabatic process,
or,
=
= 28.7 atm
Therefore, required pressure is 28.7 atm.