Sandra moves 14 m in 2 minutes. What is Sandra's average velocity (in m/s)?

2 answers:

7 0

-- If you want to talk about "velocity", you need to know the direction of the motion. There's no direction information anywhere in this question, so the best we can do is talk about Sandra's "speed".

-- Speed = (distance covered) / (time to cover the distance)

Sandra's Speed = (14 m) / (2 minutes) = 7 m/minute.

But it wants the answer in m/second.

-- (7 m/min) x (1 min/60 sec) = 7/60 m/s

Speed = 0.117 m/s

The correct answer is not on the list of choices.

Choice-B ... 0.23 m/s ... is what you would get if Sandra covered the 14 meters in ONE minute. But since it took her 2 minutes, her average speed is only half of that.

The response to this question is "none of the above" or "0.117 m/s".

tia_tia [17]4 years ago

5 0

I would say B , not sure if its correct

You might be interested in

A wheel and axle has another simple machine in it. what is it

prisoha [69]

Answer:

The wheel and axle is another simple machine. It uses a wheel with a rod attached in the middle as an axle to help it to lift or move loads. In some cases this machine works like a lever to multiply force (like with a doorknob or a fishing reel).

7 0

3 years ago

Monochromatic light from a distant source is incident on a slit 0.705 mm wide. On a screen 2.13 m away, the distance from the ce

vampirchik [111]

Answer:

492.183 nm

Explanation:

x = Distance from the central maximum to the first minimum = 1.35 mm

l = Distance of screen = 2.13 m

d = Distance of gap = 0.705 mm

m = Order = 1

We have the relation

$tan\theta=\dfrac{x}{l}\\\Rightarrow \theta=tan^{-1}\dfrac{1.35\times 10^{-3}}{2.13}\\\Rightarrow \theta=0.04^{\circ}$

$dsin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{dsin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.705\times 10^{-3}\times sin0.04}{1}\\\Rightarrow \lambda=4.92183\times 10^{-7}=492.183\ nm$