The percent of his sales for the year of the bonus is 7%
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Answer:
Step-by-step explanation:
Answer:
The table representing the number of students by which mode of transport they travel is given as:
Walk or bike Bus Car Row Total
Below age 15 87 60 18 165
Age 15 and above 65 50 80 195
Column Total 152 110 98 360
We know that a relative frequency of an event is the ratio of frequency to the total number of trials.
i..e we divide each frequencies by 360 to obtain a two-way relative frequency.
Hence,the table is given as:
Walk or bike Bus Car Row Total
Below age 15 0.24 0.17 0.05 0.46
Age 15 and above 0.18 0.14 0.22 0.54
Column Total 0.42 0.31 0.27 1
Answer:
Step-by-step explanation:
Shaded will be your numerator then count all spaces together for denominator.
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
Learn more about algebra:
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