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Fudgin [204]
3 years ago
12

Give two reasons why environmental science is important

Chemistry
1 answer:
8090 [49]3 years ago
3 0
<span>Understanding interactions between humans and the environment

</span><span>Our environment is very important to us because it influences our life. We depend largely on the environment for survival. Environment is our surrounding which makes up the relationship of people, animals, plants, and even on-living things.</span>
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The point of intercept of the plotted data with temperature axis is:
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Here is the graph, hopefully the next person can get it

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What is the smallest particle of an element that still retains all the properties of the element? a compound a mineral an atom a
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The atom is the smallest particle of an element that retains it's characteristics. Sub-atomic particles such as protons, neutrons and electrons form the atom and it is the amount of each of these sub-atomic particles that make the element that element.
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1. How many moles of HNO3 will be produced when 0.65 grams of N2O5 reacts?
fiasKO [112]
The reaction equation:
N₂O₅ + H₂O → 2HNO₃

Moles N₂O₅ = 0.65 / (14 x 2 + 16 x 5)
Moles N₂O₅ = 6.02 x 10⁻³

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3 years ago
What are the coefficients for the following chemical reaction?
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3 years ago
One gram-mole of methyl chloride vapor is contained in a vessel at 100°C and 10atm.(a) Use the ideal-gas equation of state to es
777dan777 [17]

Answer:

a) The volume of the system is 3.062 Liters.

b) Percentage error results from assuming ideal-gas behavior is 9.36%.

Explanation:

a)

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 10 atm

V = Volume of gas = ?

n = number of moles of gas = 1 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 100°C = 100+273K=373 K

Putting values in above equation, we get:

(10 atm)\times V=1 mol\times (0.0821L.atm/mol.K)\times 373 K

V=\frac{1 mol\times (0.0821L.atm/mol.K)\times 373 K}{10 atm}

V = 3.062 L

The volume of the system is 3.062 Liters.

b)

Volume of the container = V' = 2.8 L

System volume = V = 3.062 L

Percentage error of volume:

To calculate the percentage error, we use the equation:

\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100

=\frac{|3.062L-2.8 L|}{2.8 L}\times 100=9.36\%

Percentage error results from assuming ideal-gas behavior is 9.36%.

6 0
3 years ago
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