All categories

4 years ago

What materials are not good insulators of electricity?

Chemistry

2 answers:

-BARSIC- [3]4 years ago

6 0

Air, glass, plastic, wood, rubber are good insulators

Fed [463]4 years ago

5 0

Material in which we applied less external force but electron jumps from conduction band to valence band and their energy band gap is not much high... that's materials are not good insulators of electricity

You might be interested in

I WILL GIVE THE BRAINLIEST

lubasha [3.4K]

Ans 1. Both

Ans 2. Once inside plants, carbon moves through food chains, where organisms become nutrients including herbivores, carnivores and ultimately, decomposers. Once buried in the soil, carbon can be converted into fossil fuels over long periods of time and then also reenter the atmosphere by combustion. The Law of Conservation of Matter states that matter cannot be created or destroyed. The carbon cycle is an example of the Law

Ans 3. Most of the chemical energy needed for life is stored in organic compounds as bonds between carbon atoms and other atoms. The law of conservation of energy states that energy can not be created or destroyed. Thus, just like matter energy is also conserved in the process.

Hope it helps

3 0

4 years ago

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(

Mazyrski [523]

Answer is: <span>mass of calcium carbonate needed is 120 grams.
</span>Chemical reaction: CaCO₃(s) → CaO(s) + CO₂(g)<span>.
</span>V(CO₂) = 27.0 L.
Vm = 22.4 L/mol.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 27 L ÷ 22.4 L/mol.
n(CO₂) = 1.2 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
m(CaCO₃) = 1.2 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 1.2 mol · 100 g/mol.
m(CaCO₃) = 120 g.

3 0

4 years ago

Calculate the energy per photon (in J) associated with a frequency of 1260 kHz. Submit answer in scientific notation using the f

aniked [119]

Taking into account the definition of photon and energy of a photon, the energy per photon is 8.3538×10⁻³⁸ J.

<h3>Energy of a photon</h3>

Electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absortion, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression:

E=h×f

where:

E is the energy of a photon.
h is the Planck's constant h.
f is the frequency of electromagnetic radiation.

<h3>Energy per photon</h3>

In this case, you know:

h= 6.63*10⁻³⁴ Js
f= 1260 kHz= 1,260,000 Hz= 1.26×10⁶ Hz (being 1 kHz=1000 Hz)

Replacing in the definition of energy of a photon:

E= 1.26×10⁶ Hz× 6.63×10⁻³⁴ Js

Finally, the energy per photon is 8.3538×10⁻³⁸ J.

Learn more about energy of a photon:

brainly.com/question/8924116

brainly.com/question/6945706

brainly.com/question/8000078

#SPJ1

6 0

2 years ago

Which best describes the transition from gas to liquid?

Nina [5.8K]

A - its condensation and gas particles have a higher kinetic energy

8 0

3 years ago

Read 2 more answers

What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N

Citrus2011 [14]

<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis
Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.68873 \ g \ Mg_3N_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

8 0

3 years ago