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3 years ago

Which one of these graphs are a reciprocal function

Mathematics

2 answers:

Anton [14]3 years ago

8 0

Answer:

Step-by-step explanation:

The general form of a reciprocal function is r(x) = a / (x - h) + k. The graphs of reciprocal functions are made up of branches, which are the two main parts of the graph; and asymptotes, which are horizontal and vertical lines that the graph approaches but doesn't touch.

nataly862011 [7]3 years ago

4 0

Answer:

c is the correct answer

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Convert a markup of 15% on selling price to its equivalent markup on cost.

spayn [35]

Answer:

option: D is correct. ( (D) a markup of 15% on selling price is equivalent to a 85% markup on cost ).

Step-by-step explanation:

" Markup is the percentage difference between a product's cost and its selling price "

Since we are asked to Convert a markup of 15% on selling price to its equivalent markup on cost.

As there is a markup of 15% on selling price. Hence the cost of the product would be (100-15)%=85% of the selling price.

<em>Hence, a markup of 15% on selling price is equivalent to a 85% markup on cost.</em>

<em>Hence, option D is true.</em>

5 0

4 years ago

PLEASE HELP ME: the ratio of cars to trucks on a highway at any given time is 12 to 8. If there are always more than 105 cars on

andre [41]

Answer:

Step-by-step explanation:

First, set up the ratio of c:t, which is 12:8. Then set up your new ratio of c:t, which is 105:?. The way I find the easiest is to divide 105 by 12, which is 8.75, then multiply that by 8, which is 70. To check if it's right, just divide 12 by 8, and 105 by 70, and if they're the same number, you've got it right.

Ps. I'm guessing you meant to ask the minimum number of trucks, not cars.

5 0

2 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

4 years ago

Is 42° correct?? Please help

Romashka [77]

X=40 degrees because it s on the circle. arc AD+arc DC=180 arc DC is 100 so AD is 80. That means x must be 40.

7 0

4 years ago

Find YZ. please help!!!

Ad libitum [116K]

Your picture is a bit blurry. What is the equation on WX and on ZY?

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3 years ago