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kompoz [17]
3 years ago
10

What characteristics of a force can be measured?

Physics
1 answer:
Helga [31]3 years ago
6 0
Direction and Strength can be measured of force 
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The speed of light in ________ is about 230 million m/s.
Vladimir [108]

Answer:

Water

Explanation:

The speed of light in water is about 230 million m/s.

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If an engine cannot be 100%
geniusboy [140]

Answer: Given the evidence in the explanation, I'm pretty sure it's C. It still exists, but in a different form.

Explanation: "Some part of the energy supplied is used to change the internal energy of the system. Some part is also released into the surroundings. Generally, frictional losses are more predominant for the machines being not 100% efficient. This friction leads to the loss of energy in the form of heat, into the surroundings."

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Why is the milky way galaxy not expanding together with the rest of the universe?
tamaranim1 [39]
Because it on by it's self floating around not forming part of something

8 0
4 years ago
A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the h
icang [17]

Answer:

Part a)

P = 5.72 kg m/s

Part b)

\Delta P = 2.93 kg m/s

Part c)

F = 44.4 N

Part d)

\Delta P = 5.02 kg m/s

Part e)

\Delta t = 0.113 s

Part f)

\Delta K = 0

Explanation:

As we know that initial velocity of the ball is given as

v = 11.8 cos29 \hat i + 11.8 sin29 \hat j

v_i = 10.3 \hat i + 5.72 \hat j

Now final velocity of the system is given as

v_f = 10.3\hat i - 5.72\hat j

Part a)

now magnitude of initial momentum is given as

P = mv

P = 0.256(11.8)

P = 5.72 kg m/s

Part b)

Change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(5.72 + 5.72)

\Delta P = 2.93 kg m/s

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

F = \frac{\Delta P}{\Delta t}

F = \frac{2.93}{0.066}

F = 44.4 N

Part d)

Magnitude of change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(7.8 + 11.8)

\Delta P = 5.02 kg m/s

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

\frac{\Delta P}{\Delta t} = F

\frac{5.02}{\Delta t} = 44.4

\Delta t = 0.113 s

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

\Delta K = 0

8 0
3 years ago
Can someone help me please. i will give you a brainliest. thanks!​
steposvetlana [31]

Answer:

sry don't know but can u give me brainlliest

5 0
4 years ago
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