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Katen [24]
4 years ago
13

How often should cardio exercises be performed? A. Never B. Three to five times a month C. Three to five times a week D. Three t

o five times a day
Physics
2 answers:
EleoNora [17]4 years ago
6 0

Answer:

C. Three to five time a week.

Explanation:

Kobotan [32]4 years ago
4 0
C- three to five times a week
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A positive statement is:________. a. reflects oneâs opinions. b. can be shown to be correct or incorrect. c. a value judgment. d
kenny6666 [7]

Answer:

b

Explanation:

8 0
3 years ago
What are the advantages of using a telescope compared to making observations with the naked eye?
lara31 [8.8K]
The naked eye is very limited. Unlike the telescope which can see far away.
4 0
4 years ago
In which of the following cases is work being done on an object? Question 2 options: Pushing against a locked door Carrying a bo
Serggg [28]

As we know that work done is defined as product of force and displacement in the direction of applied force

so we can say it is

W = F.d

or we can say

W = Fdcos\theta

so we will have following options

A)Pushing against a locked door

There is no work done in above case as there will be no displacement in that case so work done is ZERO

B) Carrying a box down a corridor

While we move done and carrying a box then work done by gravity on the box while our work done is negative work.

C) Pulling a trailer up a hill

In above case our work done to pull a box up a hill is positive work as we need to work against gravity

D)  Suspending a heavy weight with a strong chain

During suspension there is no displacement so there will be no work done in above case

so correct answer will be

<em>Pulling a trailer up a hill</em>


6 0
4 years ago
Read 2 more answers
What would decrease the resistance of wires carrying an electric current
Anettt [7]
The answer is A. shorter wires

6 0
3 years ago
Read 2 more answers
How to calculate? I got 15000N for (a)
MAXImum [283]
Your answer for part a is correct.  Using Newton's 3rd Law, the force on the rocket by the exhaust leaving the rocket is the same magnitude (opposite direction) as the downward force applied to the exhaust.
In part b the net force is the upward force from the exhaust thrust minus the downward force of gravity:

F_{net}=F_{thrust}-mg=15,000N-1500kg \times 1.6 \frac{m}{s^2}=12,600N

Then using the Second Law, we get for part c:

F=ma \\ a= \frac{F}{m} = \frac{12600N}{1500kg} =8.4 \frac{m}{s^2}

The force and acceleration are in the upward direction
3 0
3 years ago
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