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Umnica [9.8K]
4 years ago
13

Calculate the value of the error (only) with one decimal place for: (21+1-14%) x (14 +1-9%) Please enter the answer without +- s

ign
Physics
1 answer:
Brrunno [24]4 years ago
8 0

Answer:

 6.9.

Explanation:

In case of product of two physical quantities with errors , the rule is that the product will contain error equal to the sum of percentage errors of the two physical quantities. Foe example  P contains 2% error and Q contains 3% error then P X Q will contain 2 +3 = 5 % error.

(21 ± 1.14 %) x (14±1.9%)

Total percentage error in the result of product

1.14 + 1.19 = 2.33 %.

Produce value = 21 x 14 = 294

percent of error in it = 2.33%

value of error

= 2.33% of 294

= 6.8502 or 6.9.

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Two objects, M = 15.3 ks and m = 8.29 kg are connected with an ideal string and suspended by a pulley (which rotates with no fri
Scilla [17]

Answer:

(a) 7 m/s

(b) 931 rad/s

(c) 0.716 s

Explanation:

Gravity would be exerting on the 2 masses

G_1 = Mg = 15.3*9.81 = 150.093N

G_2 = mg = 8.29*9.81= 81.32N

Since heavier, mass 1 (M) would be the one pulling down, while mass 2 is being pulled up.

So the net force on mass 1 is

F = G_1 - G_2 = 68.77N

This force would generate torque on the solid pulley

T = FR = 68.77 * 0.0075 = 0.5158 Nm

We can also calculate the pulley moments of inertia, with it being solid

I = 0.5MpR^2 = 0.5*14.1*0.0075^2 = 0.000396563kgm^2

From there we can calculate the angular acceleration of the pulley, which generates the entire system motion

\alpha = \frac{T}{I} = \frac{0.5158}{0.000396563} = 1300.58 rad/s^2

Since the system is moved by a distance of d = 2.5m, the pulley would have turn an angle of

\theta = \frac{d}{R} = \frac{2.5}{0.0075} = 333 rad

(c)The time it takes to get to this distance is

\theta = \frac{\alpha t^2}{2}

t^2 = \frac{2\theta}{\alpha} = \frac{2*333}{1300.58} =0.513

t = \sqrt{0.513} = 0.716s

(b)The final angular speed of the disk is

\omega = \alpha t = 1300.58*0.716 = 931 rad/s

(a) And so the perimeter speed of the pulley, which is also speed of mass 1 when it comes to d = 2.5 m is

v = \omega R = 931*0.0075 \approx 7m/s

5 0
3 years ago
Can someone help? pls
Vladimir79 [104]

Answer:

I do believe its B because its parallel

Explanation:

8 0
3 years ago
Read 2 more answers
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notsponge [240]

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C=\frac{2\pi \epsilon o L}{ln (b/a)} where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.

Finally we also kwn that C=Q/ΔV

then we have

ΔV =Q/C

ΔV = 12 * 10^-12/17.65*10^-12= 0.68V

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3 years ago
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a_sh-v [17]
The answer is liquid.
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Answer:

Objective: It is raining. Subjective: I love the rain!

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