Answer:
<em>Is it NOT possible for both particles to be at rest after the collision</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total linear momentum of a system of particles is conserved regardless of their internal interactions while no external force is applied to the system. If 
and 
are the masses of two particles, and only one of them is at rest, there is a non-zero total linear momentum, i.e.
if at least one of the speeds is not zero, the total initial linear momentum is not zero.
If after the collision, both particles remain at rest, both speeds will be zero and the total linear momentum won't be conserved.
So, is it NOT possible for both particles to be at rest after the collision
<span>They are balanced. If the forces were not balanced the book would move*. In this example, the downward force of gravity on the book is counterbalanced by the upthrust of the desk. </span>
Answer: The correct explanation is 2.
Explanation: The warm air is less dense (it expands) and thus it is lighter than the cold air so it will rise up to the floor. Therefore, when you place the heater on the floor it will warm the cold air which would then rise and be replaced by more cold air which would again get warm and rise and so on until the room is heated. This means that the correct explanation is 2.
On the other hand, if you put the heater at the ceiling, it will warm the cold air near the ceiling which would stay up there (it is lighter than the cold air under it). This means that the only way for the heat to spread from this ceiling level warm air to the lower levels is via conduction which is slow.
Answer:
D
Explanation:
Just had the same question and couldnt find and answer so i guessed. heres the answer no lol!
Answer:
Acceleration of the meteorite, 
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
So, the deceleration of the Meteorite is 
. Hence, this is the required solution.
