Answer:
A C6H12O6 will be the empirical formulae.
Answer is: orbitals are regions of the most probable location of electrons.
Each orbital in an atom is characterized by a unique set of values of the three quantum numbers n, l, and ml.
Magnetic quantum number (ml) specifies the orientation in space of an orbital of a given energy and shape . Magnetic quantum number divides the subshell into individual orbitals which hold the electrons, there are 2l+1 orbitals in each subshell. For example, p orbitals (and their electrons) have three orientations in spase (px, py and pz).
Principal quantum number (n) describes the size of the orbital. There are one s orbital (angular quantum number l=0), three p orbitals (angular quantum number l=1 and magnetic quantum number ml = -1,0,+1) and five d orbitals (angular quantum number l=2 and magnetic quantum number ml = -2,-1,0,+1,+2).
Since this has to do with titration, the measured volume of NaOH used would be less than the actual volume used because some of the unused NaOH would cling to the sides of the buret and therefore wouldn't factor into the measurement
Hope this helps
Answer:
E = NA/R^n - N alpha e^2/ (4 piEoR')
Explanation:
Where N = number of positive ion pairs
e= magnitude
R= interatomic distance
n = the Born exponent
Na₂O is an ionic compound. Na is in group 1 which means it has one electron in the outer shell. O is in group 6 so it has 6 electrons in the outer shell.
To become stable atoms need to either lose the electrons in the outer shell or gain electrons to gain a complete outer shell configuration.
To become stable Na loses its outer electron and becomes positively charged. It only loses one electron, so net charge is +1. O to become stable gains 2 electrons to complete its outer shell and becomes negatively charged. since it gains 2 electrons, the net charge is -2.
cation - Na⁺
anion - O²⁻
O gains 2 electrons but Na can give only one electron, therefore 2 Na⁺ ions are required.
the compound can be written by exchanging the charges
ions Na⁺ O²⁻
charge +1 -2
exchange Na₂O
Correct answer is <span>Na has +1 charge and O has -2 charge</span>