Steps to identify a mineral

atroni [7]

The last one would be false

3 0

3 years ago

The asthenosphere is the part of the upper mantle just below the lithosphere that os involved in the plate tectonic movement anf

likoan [24]

Answer:C

Explanation:

3 0

3 years ago

iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?

satela [25.4K]

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

$7.86 \ g/cm^3$

Mass of block of metal,

$18.2 \ gm$

Volume of block,

$2.56 \ cm^3$

By using the formula,

→ $Density = \frac{Mass}{Volume}$

then,

→ The density of block will be:

= $\frac{Mass}{Volume}$

= $\frac{18.2}{2.56}$

= $7.11 \ gm/cm^3$

Learn more:

brainly.com/question/10804879

7 0

2 years ago

Who is the editor in chief of The Washington Post?.

Stels [109]

Steven Ginsberg named managing editor of The Washington Post, rounding out senior management team

6 0

2 years ago

When 25.0 g of ch4 reacts completely with excess chlorine yielding 45.0 g of ch3cl, what is the percentage yield, according to c

Ber [7]

Taking into account definition of percent yield, the percent yield for the reaction is 57.08%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + Cl₂ → CH₃Cl + HCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole
Cl₂: 1 mole
CH₃Cl: 1 mole
HCl: 1 mole

The molar mass of the compounds is:

CH₄: 16 g/mole
Cl₂: 70.9 g/mole
CH₃Cl: 50.45 g/mole
HCl: 36.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole ×16 g/mole= 16 grams
Cl₂: 1 mole ×70.9 g/mole= 70.9 grams
CH₃Cl: 1 mole ×50.45 g/mole= 50.45 grams
HCl: 1 mole ×36.45 g/mole= 36.45 grams

Mass of CH₃Cl formed

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 50.45 grams of CH₃Cl, 25 grams of CH₄ form how much mass of CH₃Cl?

$mass of CH_{3} Cl=\frac{25 grams of CH_{4}x 50.45grams of CH₃Cl }{16 grams of CH_{4}}$

<u><em>mass of CH₃Cl= 78.83 grams</em></u>

Then, 78.83 grams of CH₃Cl can be produced from 25 grams of CH₄.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

$percent yield=\frac{actual yield}{theorical yield}x100$

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know: