Answer:
1750mL
Explanation:
First let us calculate the number of mole of NaOH. This is illustrated below:
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH = 17.5g
Number of mole = Mass /Molar Mass
Number of mole of NaOH = 17.5/40 = 0.4375mol
Next, let us calculate the molarity of NaOH. This is illustrated below:
Mole = 0.4375mol
Volume = 350mL = 350/1000 = 0.35L
Molarity = mole /Volume
Molarity of NaOH = 0.4375/0.35 = 1.25M
Now, let us write a balanced equation for the reaction.
NaOH + HNO3 —> NaNO3 + H2O
From the equation,
nA = 1
nB = 1
Now we can calculate the volume of the acid by doing the following:
Ma = 0.250 M
Va =?
Mb = 1.25M
Vb = 350mL
MaVa / MbVb = nA/nB
0.250 x Va / 1.25 x 350 = 1
Cross multiply to express in linear form
0.250 x Va = 1.25 x 350
Divide both side by the 0.250
Va = (1.25 x 350) / 0.250
Va = 1750mL
Therefore, the volume of HNO3 required is 1750mL