Answer:
The % yield of CO2 is 85.05 %
Explanation:
Step 1: Data given
Mass of octane = 702 grams
Molar mass octane = 114.23 g/mol
Mass CO2 =1.84 kg = 1840 grams
Molar mass of CO2
Step 2: The balanced equation
2C8H18 + 25O2 → 16CO2 + 18H2O
Step 3: Calculate moles of octane
Moles octane = mass octane / molar mass octane
Moles octane = 702.0 grams / 114.23 g/mol
Moles octane = 6.145 moles
Step 4: Calculate moles of CO2
For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O
For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles
Step 5: Calculate mass of CO2
Mass CO2 = moles CO2 * molar mass CO2
Mass CO2 = 49.16 moles * 44.01 g/mol
Mass CO2 = 2163.5 grams
Step 6: Calculate % yield of carbon dioxide
% yield = (actual yield / theoretical yield)*100%
% yield = (1840/2163.5)*100%
% yield = 85.05 %
The % yield of CO2 is 85.05 %
