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Klio2033 [76]
3 years ago
7

Find three consecutive odd integers with a sum of 75

Mathematics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

23, 25, 27

Step-by-step explanation:

first integer will be X, second will be (X+2), and the third will be (X+4). They will all be summed up and set equal to 75.

(x) + (x + 2) + (x + 4) = 75

combine like terms:

3x + 6 = 75

subtract 6:

3x = 69

divide by 3 to find value of X:

\frac{3x}{3}  =  \frac{69}{3}

x = 23

plug in X in o red der to finger the rest of the integers.

(X+2)= (23+2)=25

(X+4)= (23+4)=27

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snow_lady [41]

Answer:

x = 2 or 3

Step-by-step explanation:

Diagonal of a rhombus bisects the vertex angles. So,

x^{2} =5x-6

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Lets factorise the eqn.

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=> x (x - 2) -3(x-2)

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Here x will have 2 values.

1) x-2=0

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3 years ago
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andre [41]
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if the number in the thousands position is equal to or greater than 5, we will add one to the thousands and convert all digits after it to zeroes.

The number we have is <span>2,042,822
Applying the above concept we will find that:
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3 years ago
1/2n+3=6 what is the solution to this equation
nata0808 [166]

Answer:

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Step-by-step explanation:

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