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Wewaii [24]
3 years ago
11

What are the intermolecular force​

Chemistry
2 answers:
N76 [4]3 years ago
8 0

Intermolecular forces are the forces which mediate interaction between molecules, including forces of attraction or repulsion which act between molecules and other types of neighboring particles.

Colt1911 [192]3 years ago
8 0

Intermolecular forces are the attractive or repulsive forces between molecules. They are separated into two groups; short range and long range forces.

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Which of the following steps will slow down the reaction between coal and oxygen?
irakobra [83]

Answer:

decrease temperature of the oxygen

Explanation:

5 0
3 years ago
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The enzyme, phosphoglucomutase, catalyzes the interconversion
Fittoniya [83]

Answer:

K_{eq = 19

ΔG° of the reaction forming glucose 6-phosphate =  -7295.06 J

ΔG° of the reaction  under cellular conditions = 10817.46 J

Explanation:

Glucose 1-phosphate     ⇄     Glucose 6-phosphate

Given that: at equilibrium, 95% glucose 6-phospate is  present, that implies that we 5% for glucose 1-phosphate

So, the equilibrium constant K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq= \frac{0.95}{0.05}

K_{eq = 19

The formula for calculating ΔG° is shown below as:

ΔG° = - RTinK

ΔG° = - (8.314 Jmol⁻¹ k⁻¹ × 298 k ×  1n(19))

ΔG° = 7295.05957 J

ΔG°≅ - 7295.06 J

b)

Given that; the concentration  for  glucose 1-phosphate = 1.090 x 10⁻² M

the concentration of glucose 6-phosphate is 1.395 x 10⁻⁴ M

Equilibrium constant  K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq}= \frac{1.395*10^{-4}}{1.090*10^{-2}}

K_{eq} = 0.01279816514  M

K_{eq} = 0.0127 M

ΔG° = - RTinK

ΔG° = -(8.314*298*In(0.0127)

ΔG° = 10817.45913 J

ΔG° = 10817.46 J

5 0
3 years ago
WILL GIVE POINTS/MARK BRAINLIST! Question 6: Types of Molecular Shapes (3 points) Identify the following molecular shapes. (0.5
Vanyuwa [196]

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B. angular or bent

C. angular

D. trigonal planar

E. linear

F. linear

Explanation:

8 0
2 years ago
The hydrogen ion concentration of a vinegar solution is 0.00010 m. how is this concentration written in scientific notation? 1.0
insens350 [35]
1.0 x 10^-4 M would be the correct answer
6 0
3 years ago
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Calculate the approximate enthalpy change, δhrxn, for the combustion of one mole of methane a shown in the balanced chemical equ
Elena L [17]
To solve for the enthalpy of reaction, we apply the Hess's Law.

ΔHrxn = ∑(ν×Hf of products) - ∑(ν×Hf of reactants)
where
v is the stoichiometric coefficient determined from the balanced reaction
Hf is the standard heat of formation; these are empirical values:
*For CH₄: Hf = <span>−74.87 kJ/mol
*For O</span>₂: Hf = 0
*For CO₂: <span>-393.5 kJ/mol 
*For H</span>₂O: <span>-241.82 kJ/mol

</span>ΔHrxn = [(2*-241.82 kJ/mol)+(1*-393.5 kJ/mol)] - [(1*−74.87 kJ/mol)+(2*0 kJ/mol)] =<em> -802.27 kJ/mol</em>
4 0
3 years ago
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