1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ycow [4]
2 years ago
13

Explain why aluminum does not react with potassium nitrate (KNO3) although it reacts with copper nitrate.

Chemistry
1 answer:
Kipish [7]2 years ago
4 0

Answer:

Potassium nitrate react with aluminum to produce potassium aluminate, aluminum oxide and nitrogen. This reaction takes place at a temperature near 400°C.

Explanation:

6KNO3 + 10Al → 6KAlO2 + 2Al2O3 + 3N2

You might be interested in
1#
Black_prince [1.1K]

Answer:

1= Magnesium

2 = Option 3 =  1s² 2s² 2p⁶

Explanation:

An electrically neutral atom consist of equal number of protons and electrons.

The answer for 1st q is magnesium because the electronic configuration showed twelve number of electrons. The atomic number of magnesium is twelve that's why this configuration is of Mg.

Mg₁₂ =  1s² 2s² 2p⁶ 3s²

The second answer is option three because has atomic number ten and third electronic configuration have ten electrons.

Ne₁₀ = 1s² 2s² 2p⁶

It is stable electronic configuration. Neon is inert because of this electronic configuration. The outer most shell is completely filled.

8 0
3 years ago
Calculate the acid dissociation constant Ka of a 0.2 M solution of weak acid that is 0.1% ionized is ________.
mars1129 [50]

Answer: acid dissociation constant Ka= 2.00×10^-7

Explanation:

For the reaction

HA + H20. ----> H3O+ A-

Initially: C. 0. 0

After : C-Cx. Cx. Cx

Ka= [H3O+][A-]/[HA]

Ka= Cx × Cx/C-Cx

Ka= C²X²/C(1-x)

Ka= Cx²/1-x

Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2

Ka= 0.2(0.001²)/(1-0.001)

Ka= 2.00×10^-7

Therefore the dissociation constant is

2.00×10^-7

7 0
2 years ago
What is the mass number of sodium
lina2011 [118]

Answer:

Explanation:

Sodium mass number 23, 11 electrons

Magnesium: neutrons = 12

aluminum : atomic number  = 13

phosporus : protons = 15

3 0
2 years ago
Read 2 more answers
(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

6 0
3 years ago
Quartzite is a coarse-grained rock derived from sandstone.
sashaice [31]
Its a metamorphic rock
6 0
3 years ago
Read 2 more answers
Other questions:
  • Write equations for the reaction of 1 mol of Barium Hydroxide with 2 Moles of hydrochloric acid
    15·1 answer
  • 25) How many total ions would be present when an ionic compound is formed between a
    11·1 answer
  • A welder has 1.873 × 102 g Fe2O3 and 94.51 g Al in his welding kit. Which reactant will he run out of first?
    6·2 answers
  • What is the difference between mass and weight in detail?
    6·1 answer
  • HELP....HELP!!! What is the relationship between DNA and chromosomes?​
    7·1 answer
  • In a particular type of cat, coat color follows the dominant/recessive pattern of inheritance. The allele for a brown coat (B) i
    5·1 answer
  • A mixture of 10cm3 of o2 and 50 cm3 of hydrogen gas sparked together to form water calculate volume of non limiting reagent left
    10·1 answer
  • 2. During asexual reproduction in paramecia, a single paramecium becomes two new
    10·1 answer
  • Write a complete chemical formula, including physical state symbol, for each element listed below in its standard state. The fir
    9·1 answer
  • How many grams of ammonia would be produced from the reaction of 2.64 moles of hydrogen gas reacting with excess nitrogen?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!