If one were to match the ratio of atoms of the elements found in this molecular formula of artificial sweetener it would be :
Carbon - 7 atoms
Hydrogen - 5 atoms
Nitrogen - 1 atom
Oxygen - 3 atoms.
We are given with the ionic equation
<span>Li+(aq) + OH−(aq) + H+(aq) + Cl−(aq) → Li+(aq) + Cl−(aq) + H2O(l)
First, let us make sure that the equation is balanced. By inspection, the species on the left is balanced with the species on the right.
Next, we must identify any spectator ions. These are ions which are present in both the reactant and product side. The spectator ions are
Li+ (aq)</span>
Cl−(aq)
Cancel out the spectator ions resulting in the net ionic equation.
OH−(aq) + H+(aq) → H2O(l) <span />
Answer:
see explanation below
Explanation:
Question is incomplete, so in picture 1, you have a sample of this question with the missing data.
Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:
A = εlc
Where:
ε: molar absortivity
l: distance of the light in solution
c: concentration of solution
However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.
the equation according to the plot is:
A = 15200c - 0.018
So solving for C for an absorbance of 0.25 is:
0.25 = 15200c - 0.018
0.25 + 0.018 = 15200c
0.268 = 15200c
c = 0.268/15200
c = 1.76x10⁻⁵ M
There are four structural isomers with the molecular formula C₄H₉Br.
You start by writhing the linear carbon chain and the you start moving the bromide atom until you find all the compounds. In our case you have bromide atom in the position 1 and 2 on the carbon chain.
Then you branch the carbon chain and you have isobutane. Here the possible positions for bromide is 1 and 2 on the primary carbon chain.