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IRISSAK [1]
3 years ago
13

PLEASE HELP I'LL GIVE YOU BRAINLIEST!!

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

C

Explanation:

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4 years ago
What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11
san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}

<u>Δn = (2)-(2+1) = -1  </u>

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K_p=  K_c\times (RT)^{-1}

4 0
3 years ago
Which of the following are advantages of the SI system?
lions [1.4K]
The correct answer is A, B and C
3 0
3 years ago
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What does an object's apparent size depend on?
ipn [44]

Answer:

D. its actual size and distance from an observer

Explanation:

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3 0
3 years ago
12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?
Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?

Putting values in above equation, we get:

0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L

Thus new volume of the gas is 7.693 L

6 0
3 years ago
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