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cestrela7 [59]
3 years ago
15

Potassium (K) combines with magnesium bromide (MgBr2) to form potassium bromide (KBr) and magnesium (Mg) during a chemical react

ion.
Which of the following shows the balanced chemical equation for this reaction?

a) K + MgBr2 = KBr + Mg
b) 2 K + MgBr2 → 2 KBr + Mg
c) 2 K + MgBr2 = KBr + 2 Mg
d) 2 K +2 MgBr2 = 2 KBr + 2 Mg
Chemistry
1 answer:
amm18123 years ago
5 0

Answer: option B - 2 K + MgBr2 = 2 KBr + Mg

Explanation:

2K + MgBr2 --> 2 KBr + Mg

On Left side: 2moles of Potassium (K) reacts with 1 mole of MgBr2

On Right side: 2 moles of KBr and 1 mole of Mg.

You will observe that the coefficient of each element on left side and Right side is balanced in option B, unlike other options.

So, option B is the answer.

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lys-0071 [83]

ke prop to v^2


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400/50x50=joules/100x100


400x2x2


1600j

8 0
3 years ago
Student Exploration: Limiting Reactants Vocabulary: chemical equation, chemical formula, chemical reaction, coefficient, limitin
SIZIF [17.4K]

Answer:

30 hot dogs

Explanation:

It is given that :

There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners

There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns

One hot dogs need 1 bun and 1 wiener to make a hot dog.

There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.

Therefore, 30 hot dogs.

And the number of extra wieners left = 32 - 30 = 2 wieners.

6 0
3 years ago
Fast pls..,.,,..,,.,.,.
OLga [1]
I believe the answer is gills

Fish's use gills to breathe, so tadpoles should use gills too

hope this helps

(got the info from a documentary i watched a couple years ago)
4 0
3 years ago
Read 2 more answers
Which phase is heat energy being released?
scZoUnD [109]

The answer is B
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6 0
3 years ago
Determine the theoretical yield and the percent yield if 21.8 g of K2CO3 is produced from reacting 27.9 g KO2 with 57.0 g CO2. T
Alex_Xolod [135]

Answer:

26.9 g

81%

Explanation:

The equation of the reaction is;

4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)

Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles

4 moles of KO2 yields 2 moles of K2CO3

0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3

Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles

2 moles of CO2 yields 2 moles of K2CO3

1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3

Hence the limiting reactant is KO2

Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g

Percent yield = actual yield/theoretical yield × 100

Percent yield = 21.8/26.9 × 100

Percent yield = 81%

5 0
3 years ago
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