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3 years ago

What type of glassware is useful for transferring liquids from a big container to a small container?

Chemistry

2 answers:

liubo4ka [24]3 years ago

6 0

Answer:

Funnel

Explanation:

For transferring liquid from a big container to small container, we need a glass ware which has a large or wide mouth or receiving end so that we can pour the liquid into it easily. There should be a small transferring end or we can say it should have tapered end. For example we may use funnel for the same.

tatuchka [14]3 years ago

3 0

A beaker? I believe

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What is the acceleration object velocity of +25m/s to rest in 5.0 s

Irina-Kira [14]

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (a) is

$a = \frac{v_{f}- v_{i}}{t}$

$v_{f}$ = 25 m·s⁻¹; $v_{i}$ = 0; $t$ = 5.0 s

∴ $a = \frac{0-25}{5.0}$ = -5.0 m·s⁻²

The negative sign tells you that the object is slowing down, i.e., it is decelerating.

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3 years ago

How many bromine are in 6NaBr?

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3 years ago

Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be

serg [7]

Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

mass of CuSO₄ = 156 g

Limiting reactant = ?

Balanced Chemical reaction

3 CuSO₄ + 2 Al ⇒ 3 Cu + Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

160 g of CuSO₄ ----------------- 1 mol

156 g ----------------- x

x = (156 x 1) / 160

x = 0.975 moles

27 g of Al -------------------------- 1 mol

29 g of Al -------------------------- x

x = (29 x 1)/27

x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical 3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental 0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.

3 moles of CuSO₄ ------------------ 3 moles of Cu

0.975 moles of CuSO₄ --------------- x

x = (0.975 x 3)/3

x = 0.975 moles of Cu were obtained.

3 0

3 years ago

Read 2 more answers

The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:

LiRa [457]

Explanation:

(a) As the given chemical reaction equation is as follows.

$OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}$

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.

Hence, equation for rate law of reaction will be as follows.

Rate = $K \times [OCl^{-}] \times [l^{-}]$