When a substance goes directly from a gaseous state to a solid state as dry ice does

Physics

2 answers:

Naddik [55]3 years ago

6 0

Answer: Sublimation I think.

Explanation:

wlad13 [49]3 years ago

4 0

Answer:

Sublimation

Explanation:

not entirly sure if I'm correct

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Se dispara una bala con una velocidad de v = 300[m/s] contra un cascarón esférico de papel que gira con MCU respecto a un eje ve

Sladkaya [172]

Answer:

w = 4.712 10⁻³ rad / s

Explanation:

For this exercise, the time it takes for the bullet to travel the distance of 2R must be equal to the time that the hole must travel half a circle.

Let's start by calculating the time it takes for the bullet, which is going at constant speed.

v = x / t

t = x / v

t = 2R / v

t = 2 0.10 / 300

t = 6.666 10⁻⁴ s

As they ask that a single hole is formed in this time, it must be rotated half a circle, that is, θ =π rad, for which we use the angular scientific relations, where the shell has constant angular velocity

w = θ / t

w = π / 6,666 10⁻⁴

w = 4.712 10⁻³ rad / s

7 0

3 years ago

A bags shed and he balls stand slap DC dmss

Natalija [7]

Answer:

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7 0

3 years ago

A 2. 5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.

OLga [1]

The speed of the spring when it is released is 3.5 m/s.

The given parameters:

Mass of the block, m = 2.5 kg
Spring constant, k = 56 N/m
Extension of the spring, x = 0.75 m

The speed of the spring when it is released is calculated by applying the principle of conservation of energy as follows;

$K.E = U_x\\\\\frac{1}{2} mv^2 = \frac{1}{2} kx^2\\\\mv^2 = kx^2\\\\v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{56 \times 0.75^2}{2.5} } \\\\v = 3.5 \ m/s$