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Romashka [77]
3 years ago
11

A ball is attached to a string and rotates in a circle. if it takes 1.00 s to complete one revolution, what is the angular veloc

ity of the ball?
Physics
1 answer:
Paha777 [63]3 years ago
8 0
<span>An object roating at one revokution per second has an angular velocity of 360 degrees per second or 2pi radians per second. This is found by taking the number of revolutions over a period of time and than dividing by the chosen period of time to get the velocity. There are 360 degrees or 2pi radians in one revolution.</span>
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Consider a turntable to be a circular disk of moment of inertia It rotating at a constant angular velocity ωi around an axis thr
Rom4ik [11]

Answer:

Note: Angular momentum is always conserved in a collision.

The initial angular momentum of the system is

L = ( It ) ( ωi )

where It = moment of inertia of the rotating circular disc,

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The final angular momentum is

L = ( It + Ir ) ( ωf )

where ωf is the final angular velocity of the system.

Since the two angular momenta are equal, we see that

( It ) ( ωi ) = ( It + Ir ) ( ωf )

so making ωf the subject of the formula

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A ladder placed up against a wall is sliding down. The distance between the top of the ladder and the foot of the wall is decrea
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Answer:

distance changing at rate of 3.94 inches/sec

Explanation:

Given data

wall decreasing at a rate = 9 inches per second

ladder L = 152 inches

distance  h = 61 inches

to find out

how fast is the distance changing

solution

we know that

h² + b² = L²   ..................1

h² + b² = 152²

Apply here derivative w.r.t. time

2h dh/dt + 2b db/dt = 0

h dh/dt + b db/dt = 0

db/dt = - h/b × dh/dt     .............2

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we know

h = 61

so h² + b² = L²

61² + b² = 152²

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so b = 139.223

and we know dh/dt = -9 inch/sec

so from equation 2

db/dt = -61/139.223  (-9)

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db/dt = 3.94 inches/sec

distance changing at rate of 3.94 inches/sec

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