Answer:
The total mechanical energy of a pendulum is conserved neglecting the friction.
Explanation:
- When a simple pendulum swings back and forth, it has some energy associated with its motion.
- The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
- The potential energy of the simple pendulum is given by P.E = mgh
- The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
- When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
- When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
- Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.
Downward force acting on the ball is 19.6N
Net force acting on the ball is 1960V N
<u>Explanation:</u>
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Given:
Mass of the ball, m = 2kg
Density of ball, σ = 800 kg/m³
Density of water, ρ = 1000 kg/m³
Downward force acting by the ball in the vessel = mg
where, g = 9.8m/s²
F = 2 X 9.8
F = 19.6N
Net force acting on the ball:
Fnet = (ρ - σ) Vg
where,
V is the volume of water
Fnet = (1000 - 800) V X 9.8
Fnet = 1960V N
If the volume is known, then substitute the value of V to find the net force.
Thus, Downward force acting on the ball is 19.6N
Net force acting on the ball is 1960V N
Answer:
|X| = 72 cm
Explanation:
We need to find the magnitude of vector X.
Vector Y = 21 cm
Vector Z = 75 cm
We know that, the magnitude of resultant vector is given by :
So, the value of magnitude of vector X is 72 cm
Water is a really good conductor of sound so I would have to say that it would be to send the message underwater because a more dense medium produces a louder sound
Answer:
The pressure of the water in the pipe is 129554 Pa.
Explanation:
<em>There are wrongly written values on the proposal, the atmospheric pressure must be 101105 Pa, and the density of water 1001.03 kg/m3, those values are the ones that make sense with the known ones.</em>
We start usign the continuity equation, and always considering point 1 a point inside the pipe and point 2 a point in the nozzle:
We want 
, and take into account that the areas are circular:
Substituting values we have (we don't need to convert the cm because they cancel out between them anyway):
For determining the absolute pressure of the water in the pipe we use the Bernoulli equation:
Since the tube is horizontal 
and those terms cancel out, so the pressure of the water in the pipe will be:
And substituting for the values we have, considering the pressure in the nozzle is the atmosphere pressure since it is exposed to it we obtain:
