Is this a true and false question?
Answer:
Kinetic energy of the brick is 26.4 Joule
Answer:
Explanation:
The resulting valie would be too large
Answer:
Part a)

Part 2)

Part 3)

Explanation:
Part 1)
As we know that electric field and potential difference related to each other as

so we will have


so we have


Part 2)
Charge of an electron

now force is given as



Part 3)
Work done to move the electron


