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2 years ago

9

8.

1 answer:

eimsori [14]2 years ago

3 0

B. Unbalanced force

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Calculate the kinetic energy of a 2.2kg brick when it has a speed of 4.9m/s

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2 years ago

1. A pair of oppositely charged parallel plates is separated by 5.51 mm. A potential difference of 614 V exists between the plat

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Answer:

Part a)

$E = 1.11 \times 10^5 N/C$

Part 2)

$F = 1.78 \times 10^{-14} N$

Part 3)

$W = 5 \times 10^{-17} J$

Explanation:

Part 1)

As we know that electric field and potential difference related to each other as

$E = \frac{\Delta V}{x}$

so we will have

$\Delta V = 614 V$

$x = 5.51 mm$

so we have

$E = \frac{614}{5.51 \times 10^{-3}}$

$E = 1.11 \times 10^5 N/C$

Part 2)

Charge of an electron

$e = 1.6 \times 10^{-19} C$

now force is given as

$F = qE$

$F = (1.6 \times 10^{-19})(1.11 \times 10^5)$

$F = 1.78 \times 10^{-14} N$

Part 3)

Work done to move the electron

$W = F.d$

$W = (1.78 \times 10^{-14})(5.51 - 2.7) \times 10^{-3}$

$W = 5 \times 10^{-17} J$

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3 years ago