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Komok [63]
3 years ago
5

A5 kg box slides 3 m across the floor before coming to rest. What is the coefficient of kinetic friction between the floor and t

he box if the box had an initial speed of 3 m / s?
Physics
1 answer:
frutty [35]3 years ago
6 0

Answer:

Coefficient of kinetic friction (Cof. KE) = 0.153

Explanation:

Given:

Mass of box (M) = 5 kg

Distance = 3 m

Initial speed (v) = 3 m/s

Find:

Coefficient of kinetic friction (Cof. KE)

Computation:

v² = u² + 2as

a = v² / 2s

a = 9 / 2(3)

a = 1.5 m/s²

Coefficient of kinetic friction (Cof. KE) = a / g

Coefficient of kinetic friction (Cof. KE) = 1.5 / 9.8

Coefficient of kinetic friction (Cof. KE) = 0.153

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Which option lists a form of potential energy followed by a form of kinetic energy?
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(B) is correct option.

Explanation:

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Lists a form of potential energy followed by a form of kinetic energy

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