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sasho [114]
3 years ago
15

Annette is stacking boxes in her closet. There are 15 boxes in all. If each box weighs 7.5 pounds, his much do the boxes weigh t

ogether
Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
If 1 box weighs 7.5 pounds, then we find the weight for 15 boxes with this equation:
15*7.5
Multiply:
112.5
15 boxes weight 112.5 pounds
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In the diagram below, the perimeter of the triangle is equal to the perimeter of the square. What is the length of a side of the
kondaur [170]

The perimeter of each is the sum of the lengths of its sides.

Triangle Perimeter = 16 + 4x-3 +3x = 7x+13

Square Perimeter = 2x +2x +2x +2x = 8x

If these are equal, you have

7x+13=8x\\\\13=x\qquad \mbox{subtract 7x}\\\\26=2x\qquad \mbox{multiply by 2}

The length of a side of the square is 26 units.

3 0
3 years ago
Will give brainliest<br> Please help with problem, I don't understand it
Alex787 [66]

Answer:

111.375

Step-by-step explanation:

each triangle are equal to each other, it equals (b x h)/2

good luck and thanks for the brainliest!

6 0
2 years ago
WILL MARK BRAINLIEST!
Dennis_Churaev [7]

Answer: A

Step-by-step explanation: Took the test |

                                                                     \/

4 0
3 years ago
The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
Amanda selected 18 pea pods at random from a bag containing about 500 pea pods. She opened each pod and counted the number of pe
kkurt [141]
C.....sorry if im wrong

6 0
3 years ago
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