Answer:
2.11 m
Explanation:
<u>Given data</u>
h=6.626×
(plank constant)
L=45.7 pm
n=n2-n1
n=5-1
n=4
<em>where,</em>
<em>n2=5</em>
<em>n1=1</em>
<u>To find:</u>
E=?
λ=? (Wavelength)
<u>solution</u>
The energy stored in an electron at a specified level is given by;
E=
×
÷8m
..........(1)
<em>m=mass of electron(9.1×</em>
)
<em>l=length of box</em>
<u>To find E</u>
putting the value of given data in eq(1)
E=9.41×
<u>To find λ</u>
λ=hc/E............................(2)
c=3×
(speed of light)
putting the value in eq 2 to find wavelength
λ=2.11 m
<u></u>
<u>Note:</u>
There is a chance in calculation error. but the method is correct to solve the problem.
Answer:
9.88 milivolt
Explanation:
Given: diameter d = 5.2 cm
magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T
t = 0.29 sec.
we know emf = - dΦ/dt
and flux Φ = BA
A= area
therefore emf ε = -A(B_2-B_1)/Δt
Answer:
vertical component = 9.7m/s
Explanation:
Vy= (23)sin25 = 9.7m/s
The work done on the car is -20 J.
Work done on the car is negative, meaning that the car actually does work on the external system.
<h3>Energy and law of conservation of energy</h3>
- Energy is the ability to do work
- the law of conservation of energy states that the total energy in a system is conserved
From the law of conservation of energy, the initial energy of the car before it moves down the road remains constant or unchanged.
- Initial energy = 100 J
- Initial energy = Final energy - work done on car
- Final Energy = Work done on car + initial energy
80J = Work done on car + 100 J
Work done on car = 80 - 100J
Work done on car = -20 J
Hence, the work done on the car is -20 J
Work done on car is negative.
Since work done on the car is negative, it means that the car actually does work on the external system. Hence, the decrease in the energy of the car.
Learn more about energy and work at: brainly.com/question/13387946
