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Otrada [13]
2 years ago
11

A 241 kg mass is lifted 1.8 m. What is the potential energy of the mass (in J)?

Physics
2 answers:
Korolek [52]2 years ago
6 0

Answer:

mass is lifted 1.8 m. What is the potential energy of the mass 4. A 100 kg

Nitella [24]2 years ago
4 0
4251.24 Joules
Using acceleration as 9.8m/s^2,241*1.8*9.8
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What is championship game of baseball called? The World Series The Super Bowl The World Cup​
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The World Series

Explanation:

The Super Bowl is the championship American Football game, and the World Cup is the Soccer/Football game.

American Football and Football are different things. The first is what Americans call football, while the other is what Americans call soccer. It is confusing.

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Do magnets have to touch each other in order to experience a magnetic force
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No they do not they just need to be in each other's magnetic field
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In what state of matter are particles vibrating and moving at high speeds?
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Gas

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Two objects separated by a distance r are each carrying a charge q The magnitude of the force exerted on the second object by th
Sindrei [870]

Answer:F=4F

Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them

Force between the two charges is given by

F=K*q1*q2/r^2

if one charge become 4 times, new force is,

F=4(K*q1*q2)/r^2

F=4F

Where q1 and q2 are the point charges

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4 0
3 years ago
The speed at which a light aircraft can take off is 120 km/h. (A) What is the minimum constant acceleration required for the pla
kondor19780726 [428]

Answer:

A) a = 2.31[m/s^2]; B) t = 14.4 [s]

Explanation:

We can solve this problem using the kinematic equations, but firts we must identify the data:

Vf= final velocity = take off velocity = 120[km/h]

Vi= initial velocity = 0, because the plane starts to move from the rest.

dx= distance to run = 240 [m]

v_{f} ^{2} =v_{i} ^{2}+2*g*dx\\where:\\v_{f}=120[\frac{km}{h} ]*\frac{1hr}{3600sg} * \frac{1000m}{1km} =33.33[m/s]\\\\Replacing\\33.33^{2}=0+2*a*(240)\\ a=\frac{11108.88}{2*240}\\  a=2.31[m/s^2]\\

To find the time we must use another kinematic equation.

v_{f} =v_{i} +a*t\\replacing:\\33.33=0+(2.31*t)\\t=\frac{33.33}{2.31}\\ t=14.4[s]

7 0
3 years ago
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