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Ganezh [65]
3 years ago
13

A movie theater is 4 kilometers east and 2 kilometers south of your house.

Physics
2 answers:
kkurt [141]3 years ago
8 0
A) (4,-2) is the theater
B) (-1,1) is the restaurant
Alexxandr [17]3 years ago
7 0

a. (+4, -2)

We can use the following conventions:

- x-axis: east-west direction, with east being positive x and west being negative x

- y-axis: north-south direction, with north being positive y and south being negative y

With this coordinates, the movie theater is:

- 4 km east --> this means x = +4

- 2 km south --> this means y = -2

So, the coordinates of the theater are (+4,-2)


b. (-1,+1)

We drive 5 km west (which means \Delta x = -5) and 3 km north (which means \Delta y = +3). We have to add these displacements to each coordinate. we find:

x'= x_0 + \Delta x = +4 + (-5) = -1\\y' = y_0 + \Delta y = -2 + (+3)=+1

So, the coordinates of the restaurant are (-1, +1)


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Theo mixes cake batter and places it in the oven at 350°F for 45 minutes. Explain what type of reaction baking a cake represents
Nataly_w [17]

Baking a cake creates a endothermic reaction. When heated, the baking soda/powder reacts, the eggs change form, and everything else follows suit. The baking soda/powder creates the rising of the cake.

4 0
3 years ago
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A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe
inessss [21]

Answer:

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

a_c = \frac{V^2}{r}

Where,

V = Tangencial velocity

r = radius

With our values we know that

a_c = \frac{V^2}{r}

\frac{V^2}{r} = \frac{1}{10}g

Therefore solving to find V, we have:

V = \sqrt{\frac{1}{10}g*r}

V = \sqrt{\frac{9.81*200}{10}}

V = 14m/s

For definition we know that the Time to complete are revolution is given by

t = \frac{Perimeter}{Speed}

t = \frac{2\pi R}{V}

t = \frac{2\pi * 200}{14}

t = 1.5min

6 0
3 years ago
The cheetah is considered the fastest running animal in the world. Cheetahs can accelerate to a speed of 21.7 m/s in 2.50 s and
viktelen [127]

Answer:

1) 64.2 mi/h

2) 3.31 seconds

3) 47.5 m

4) 5.26 seconds

Explanation:

t = Time taken = 2.5 s

u = Initial velocity = 0 m/s

v = Final velocity = 21.7 m/s

s = Displacement

a = Acceleration

1) Top speed = 28.7 m/s

1 mile = 1609.344 m

1\ m=\frac{1}{1609.344}\ miles

1 hour = 60×60 seconds

1\ s=\frac{1}{3600}\ hours

28.7\ m/s=\frac{\frac{28.7}{1609.344}}{\frac{1}{3600}}=64.2\ mi/h

Top speed of the cheetah is 64.2 mi/h

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow t=\frac{21.7-0}{2.5}\\\Rightarrow a=8.68\ m/s^2

Acceleration of the cheetah is 8.68 m/s²

2)

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{28.7-0}{8.68}\\\Rightarrow t=3.31\ s

It takes a cheetah 3.31 seconds to reach its top speed.

3)

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{28.7^2-0^2}{2\times 8.68}\\\Rightarrow s=47.5\ m

It travels 47.5 m in that time

4) When s = 120 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 120=0\times t+\frac{1}{2}\times 8.68\times t^2\\\Rightarrow t=\sqrt{\frac{120\times 2}{8.68}}\\\Rightarrow t=5.26\ s

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds

8 0
3 years ago
Define escape velocity ​
lianna [129]

Answer:

the lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.

Explanation:

8 0
3 years ago
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I’ll give brainliest!! please help and answer correctly! plsss answer quick
Rashid [163]

Answer: The motion of the object will remain the same

Explanation:

6 0
3 years ago
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