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Ganezh [65]
3 years ago
13

A movie theater is 4 kilometers east and 2 kilometers south of your house.

Physics
2 answers:
kkurt [141]3 years ago
8 0
A) (4,-2) is the theater
B) (-1,1) is the restaurant
Alexxandr [17]3 years ago
7 0

a. (+4, -2)

We can use the following conventions:

- x-axis: east-west direction, with east being positive x and west being negative x

- y-axis: north-south direction, with north being positive y and south being negative y

With this coordinates, the movie theater is:

- 4 km east --> this means x = +4

- 2 km south --> this means y = -2

So, the coordinates of the theater are (+4,-2)


b. (-1,+1)

We drive 5 km west (which means \Delta x = -5) and 3 km north (which means \Delta y = +3). We have to add these displacements to each coordinate. we find:

x'= x_0 + \Delta x = +4 + (-5) = -1\\y' = y_0 + \Delta y = -2 + (+3)=+1

So, the coordinates of the restaurant are (-1, +1)


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Q=2e=2*(-1.6*10^-19) C
V=75 V

Ep=(-3.2*10^-19)*75

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Read 2 more answers
An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N
algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

<u>K.E = 15.57 x 10⁻¹⁷ J</u>

4 0
3 years ago
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