Answer:
a) 
, b) 
, c) 
.
Explanation:
a) Let assume that car travel on a horizontal surface. The equations of equilibrium of the car are:
After some algebraic handling, the following expression for the propulsion force is constructed:
b) The power require to move the car at a speed of 5 meters per second is:
c) The efficiency of the car is:
Answer:
Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².
Explanation:
The period (T) of a spring in oscillation = 2π √(m/k)............. equation 1
Where m = mass acting on the spring (kg), k = spring constant of the spring (kg/s²).
Making k the subject of equation 1
k = T²/(4π²×m) .......................... equation 2
From the question, F = 4.42 Hz,
since T = 1/F
then, T = 1/F = 1/4.42 =0.226 s, π = 3.143
since the weight of the mass is evenly distributed over the four identical spring, Hence
m = 1450/4 = 362.5 kg
Substituting these values into equation 2
k = 0.226/{(4×3.143²)362.5}
k = 0.226/(14323.751)
k = 0.0000016 kg/s²
k = 1.6 × 10⁻⁶ kg/s².
Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².
2.3 grams of wood has the same energy as 1g of oil.
The majority of wood and wood waste used as fuel in the United States is used by industry. Manufacturers of paper and wood products are the biggest industrial users. They produce steam and electricity from waste from paper and lumber mills, which saves money by lowering the number of other fuels and electricity they need to buy to run their facilities.
There are numerous power plants that primarily burn wood to produce electricity in the electric power sector, and some coal-burning power plants burn wood chips along with coal to cut down on sulfur dioxide emissions. The primary purpose of wood consumption in the business sector is heating.
To learn more about wood please visit-
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Answer:
u=36.8m/s
Explanation:
because of the acceleration is a constant acceleration we can use one of the "SUVAT" equations
u^2=v^2-2ā*s. where:
u^2 stands for intial velocity
v^2 stands for final velocity
since the cougar skidded to a complete stop the final velocity is zero.
u^2=v^2-2ā*s
u^2=(0)^2 -2(-2.87 m/s^2)*236 m
u^2=0+5.74m/s^2* 236m
u^2=1354.64m^2/s^2
u=√1354.64m^2/s^2
u=36.8m/s (approximate value)
when ever the acceleration is constant you can use one of the following equation to find the required value.
1. v = u + at. (no s)
2. s= 1/2(u+v)t. (no ā)
3. s=ut + 1/2at^2. ( no v)
4. v^2=u^2 + 2āS. (no t). 5. s= vt - 1/2at^2. (no u)
Complete question is;
An experiment is carried out to measure the extension of a rubber band for different loads.
The results are shown in the image attached.
What figure is missing from the table?
Answer:
17.3 cm
Explanation:
The image attached showed values for load, extension and initial length.
Now, the first length there is 15.2 cm and as such it's corresponding extension is 0 because it has no preceding measured length.
The second measured length is 16.2 cm. Since it's initial measured length is 15.2 cm, then the extension has a formula; final length - initial length.
This gives: 16.2 - 15.2 = 1 cm
This corresponds to what is given in the table.
For the next measured length, it is blank but we are given the extension to be 2.1 cm. Now, since the initial measured length is 15.2 cm.
Thus;
2.1 cm = Final length - 15.2 cm
Final length = 15.2 + 2.1
Final length = 17.3 cm
