Approximate the square root of 12 to the nearest integer helppppppp!!!!!!!!
1 answer:
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Options:
(12,0) (0,12) (3,-1) (0,-4/3)
Answer:
(12,0) , (3,-1) and (0,-4/3)
Step-by-step explanation:
Given
Required
Which option is true?
A coordinate point is of the form;
So, we have to substitute the x and y values in the given equation.
A. For (12,0)
and
becomes
<em>This is true</em>
B. For (0,12)
and
becomes
<em>This is false</em>
C. For (3,-1)
and
becomes
<em></em>
<em></em>
<em>This is true</em>
D. For (0,-4/3)
and
becomes
<em></em>
<em>This is true</em>
<em></em>
<em>Hence, (12,0) , (3,-1) and (0,-4/3) are true values of the equation</em>
1.
These two numbers are: -5 and -5
-5 + (-5) = -10
-5 * -5 = 25
so...
(x - 5)(x - 5)
To find the roots set the factored numbers equal to zero and solve for x:
x - 5 = 0
x = 5
2.
This equation needs to be equal to zero, so bring -14 to the other side by adding 14 to both sides
Find two numbers that the sum is equal to 9 AND the multiplication of the numbers is 14
These numbers are 7 and 2
7 + 2 = 9
7*2 = 14
so...
(x + 2) (x + 7)
To find the roots set the each of the factored numbers equal to zero and solve for x:
x + 2 = 0
x = -2
x + 7 = 0
x = -7
3.
This equation needs to be equal to zero, so bring 6x to the other side by subtracting 6x to both sides
In this equation you can factor out a 3 and an x:
3x (x - 2)
To find the roots set the each of the factored numbers equal to zero and solve for x:
3x = 0
3x/3 = 0/3
x = 0
x - 2 = 0
x = 2
Hope this helped!