What kind of electrochemical cell might likely be used for a task such a electroplating?

Ava Gadro is performing a titration in order to determine the amount of sodium hydroxide, NaOH(aq), in 81 mL of an aqueous solut

Irina-Kira [14]

Answer:

M = 0.050 M

Explanation:

WE have an acid base reaction between NaOH and HCl. The reaction is as follow:

HCl + NaOH -------> NaCl + H₂O

As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:

M₁V₁ = M₂V₂ 1: acid; 2: base

This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:

M₂ = M₁V₁ / V₂

All we have to do now is replace the given values and solve for the concentration:

M₂ = 0.15 * 27 / 81

<h2>M₂ = 0.050 M</h2><h2>This is the concentration of the base</h2>

5 0

3 years ago

n the formation of chloromethane and hydrogen chloride. The overall reaction is 2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g) 2CH4(g

IrinaVladis [17]

Answer:

The total pressure in the flask is 0,619 atm.

Explanation:

For the reaction:

2CH₄(g) + 3Cl₂(g) ⟶ 2 CH₃Cl(g) + 2HCl(g) + 2Cl⁻(g)

The moles of CH₄ in 295 mL at STP are:

n = PV/RT

Where P is pressure (1 atm), V is volume (0,295L), R is gas constant (0,082atmL/molK) and T is temperature (273,15 K)

Replacing, moles of CH₄ are <em>0,0132 moles</em>

In the same way, moles of chlorine are <em>0,0324 moles</em>

As 3 moles of Cl₂ react with 2 moles of CH₄, for a total reaction of 0,0132 moles of CH₄ you need:

0,0132 moles CH₄ × $\frac{3 moles Cl_{2}}{2 moles CH_{4}}$ = <em>0,0198 moles Cl₂. </em>That means that 0,0324-0,0198 = <em>0,0126 moles of Cl₂ are in excess.</em>

As the reaction reaches in 77%, the moles of CH₄ that don't react are:

0,0132×(100%-77%)= <em>3,036x10⁻³ moles of CH₄</em>

Also, the moles of Cl₂ that don't react are:

0,0126 + 0,0198×(100%-77%)= <em>0,0172 moles of Cl₂</em>

The moles produced of each compound are:

0,0132×77% × $\frac{2 moles CH_{3}Cl}{2 moles CH_{4}}$ = <em>0,0102 moles of CH₃Cl -</em><em>that are the same moles of HCl and Cl⁻</em><em>-</em>

Thus, total moles in the flask are:

<em>3,036x10⁻³ moles of CH₄ + 0,0172 moles of Cl₂ + 0,0102 moles of CH₃Cl + 0,0102 moles of HCl + 0,0102 moles of Cl⁻ = </em><em>0,0507 total moles</em>

As the volume of the flask is 2,00L and the final temperature is 298 K. The total pressure in the flask is:

P = nRT/V

I hope it helps!

3 0

3 years ago

(3.605 X 10^-27) + (4.01 X 10^-25)<br> Answer in scientific notation

Greeley [361]

The answer is 4.04605 X 10^-25

3 0

3 years ago

A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?

Anni [7]