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SVETLANKA909090 [29]
2 years ago
10

How many grams of silver are present in 12.044 x 1023 atoms of Ag?

Chemistry
1 answer:
Leno4ka [110]2 years ago
4 0

Answer:

The correct answer is 201.7 g

Explanation:

Silver is a chemical element which symbol is Ag. From the Periodic Table, the molar mass of Ag is 100.86 g/mol. Also, we know that 1 mol of atoms is equal to 6,022 x 10²³atoms (Avogadro's number). So, we have the following relations (convertion factors):

1 mol Ag atoms = 6,022 x 10²³ atoms

1 mol Ag = 100.86 g

We use this factors and we calculate the grams og Ag as follows:

g Ag = 12.044  x 10^{23} x \frac{1 mol Ag}{6.022 x 10^{23} atoms } x \frac{100.86 g}{1 mol Ag} = 201.7 g

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Calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution​
sineoko [7]

Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject

Explanation:  so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³  so all we have to do is to find the molecular relative mass(mr) .

to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.

NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass

now we fix it in our formulae which is m=n× mr

m=1.5× 40 =60 so our mass is 60grams or 60g

HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment

8 0
3 years ago
What would be the best title for the blue circle
Andrej [43]
The answer will  be Experimental investigations involve a process in which a "fair test" is designed and variables are actively manipulated, controlled, and measured in an effort to gather evidence to support or refute a causal relationship. Experimental investigations have a control group which does not receive any treatment.
5 0
3 years ago
A metal is found that has a mass of 27g and will displace 6mL of water. Calculate its density and identify the metal.
melisa1 [442]

The density of metal = 4.5 g/ml, and the metal = Titanium

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

mass of metal=27 g

volume = 6 ml

The density :

\tt \rho=\dfrac{27}{6}\\\\\rho=4.5~g/ml

The metal with a density of 4.5 g/ml is Titanium

3 0
2 years ago
THIS IS URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Pani-rosa [81]

Answer:

1- 1.54 mol.

2- 271.9 kPa.

3- Yes, the tires will burst.

4- 235.67 kPa.

5- As, the temperature increased, the no. of molecules that has minimum kinetic energy increases as shown in image 1 that represents the Maxwell’s Distribution of Speeds of molecules. "Kindly, see the explanation and the attached images".

<em>Explanation:</em>

<em>Q1- How many moles of nitrogen gas are in each tire?  </em>

  • To calculate the no. of moles of nitrogen gas in each tire, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the nitrogen gas (P = 247.0 kPa/101.325 = 2.44 atm),

V is the volume of the nitrogen gas (V = 15.2 L),

n is the no. of moles of the nitrogen gas (n = ??? mole),

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the nitrogen gas (T = 21°C + 273 = 294 K).

∴ n = PV/RT = (2.44 atm)(15.2 L)/(0.082 L/atm/mol.K)(294.0 K) = 1.54 mol.

<em>Q2: What would the maximum tire pressure be at 50 degrees C?  </em>

  • Now, the temperature is raised to be 50°C (T = 50°C + 273 = 323 K).
  • The pressure can be calculated using the general gas law: PV = nRT.

<em>∴ P = nRT/V </em>= (1.54 atm)(0.082 L/atm/mol.K)(323.0 K)/(15.2 L) = 2.68 atm = <em>271.9 kPa.</em>

<em>Q3: Will the tires burst in Moses Lake? Explain.</em>

  • <em>Yes,</em> the tires will burst because the internal pressure be 271.9 kPa that exceeds 270 kPa, the pressure above which the tires will burst.

<em>Q4: If you must let nitrogen gas out of the tire before you go, to what pressure must you reduce the tires before you start your trip? (Assume no significant change in tire volume.)  </em>

  • To get the pressure that we must begin with:
  • Firstly, we should calculate the no. of moles at:

T = 55°C + 273 = 328 K,

Pressure = 270 kPa (the pressure above which the tires will burst). (P =270 kPa/101.325 = 2.66 atm).

V = 15.2 L, as there is no significant change in tire volume.

∴ n = PV/RT = (2.66 atm)(15.2 L)/(0.082 L.atm/mol.K)(328 K) = 1.5 mol.

  • 1.5562 moles of N₂ in the tires will give a pressure of 270 kPa at 55°C, so this is the minimum moles of N₂ that will make the tires burst.
  • Now, we can enter this number of moles into the original starting conditions to tell us what pressure the tires will be at if we start with this number of moles of N₂.

P = ???  

V = 15.6 L.

n = 1.5 mol

T = 21°C + 273 = 294.0 K  

R = 0.0821 L.atm/mol.K.

∴ P = nRT/V = (1.5 mol x 0.082 x 294.0 K) / (15.6 L) = 2.2325 atm = 235.67 kPa.

<em>So, the starting pressure needs to be 235.67 kPa or just under in order for the tires not to burst.</em>

<em />

<em>Q5: Create a drawing of the tire and show a molecular view of the air molecules in the tire at 247 kpa vs the molecular view of the air molecules after the tires have been heated. Be mindful of the number of molecules that you use in your drawing in the before and after scenarios. Use a caption to describe the average kinetic energy of the molecules in both scenarios.</em>

<em />

  • As, the temperature increased, the no. of molecules that has minimum kinetic energy increases as shown in “image 1” that represents the Maxwell’s Distribution of Speeds of molecules.
  • The no. of molecules that possess a critical K.E. of molecules increases due to increasing the temperature activate the motion of molecules with high velocity as
  • (K.E. = 3RT/2), K.E. directly proportional to the temperature of the molecules (see image 2).
  • Also, the average speed of molecules increases as the K.E of the molecules increases (see image 3).

3 0
2 years ago
A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.
scoray [572]
The right subject for this question is physics.

To calculate the work you use the formula:

Work = force * displacement

Work = 2500 pounds * 30 feet = 75,000 pounds - feet



To calculate the power you use the formula:

power = work / time

Power = 75,000 pound - feet / 30 seconds = 2300 pound-feet / second.
3 0
3 years ago
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