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Mariulka [41]
3 years ago
12

Which of the following electron configurations is incorrect? A) S [Ne]3s³3p⁴ B) Sn [Kr]5s²4d¹⁰5p² C) Rb [Kr]5s¹ D) V [Ar]4s²3d³

E) I [Kr]5s²4d¹⁰5p⁵
Chemistry
1 answer:
Verizon [17]3 years ago
4 0

Answer:

A S [Ne]3s³3p⁴ instead of [Ne]3s²3p⁴

Explanation:

Hello,

To find the incorrect electronics configuration, we have to refer back to our periodic table or simply writing the electronic configuration of each element down follow principles guiding it such as Aufbau principle and Hund's rule.

a) S = [Ne] 3s³ 3p⁴ instead of [Ne] 3s²3p⁴

Option A is wrong.

S orbital can only accommodate a maximum of 2 electrons and in this case, 3s orbital is carrying 3 electrons. This has violated the rule.

b) Sn = [Kr] 5s² 4d¹⁰ 5p²

Option B is correct

c) Rb = [Kr] 5s¹

Option c is correct

d) V = 4s² 3d³

Option D is correct

e) I = [Kr] 5s² 4d¹⁰ 5p⁵

From the above, we can see that the answer is option A = S

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β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.

Explanation:

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3 years ago
How many grams of mercury would be contained in 15 compact fluorescent light bulbs?
zhenek [66]

Answer:

Grams of mercury= 0.06 g of Hg

Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

Explanation:

Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

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Therefore, 60 mg = 0.001 g * 60 = 0.06 g of mercury.

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3 years ago
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Answer:

Molar heat of solution of KBr is 20.0kJ/mol

Explanation:

Molar heat of solution is defined as the energy released (negative) or absorbed (Positive) per mole of solute being dissolved in solvent.

The dissolution of KBr is:

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In the calorimeter, the temperature decreases 0.370K, that means the solution absorbes energy in this process. The energy is:

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q = 0.5032kJ

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Thus, molar heat of solution of KBr is:

0.5032kJ / 0.0252moles = <em>20.0kJ/mol</em>

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3 years ago
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