All categories

3 years ago

Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine total displacement of

Physics

2 answers:

Vladimir79 [104]3 years ago

6 0

B. 2 Km North, displacement is basically how far form the original place

Goshia [24]3 years ago

3 0

Answer:

i am not sure about the right answer but i took the test and the answer is not 2km

Explanation:

You might be interested in

Using a dish-shaped mirror, a solar cooker concentrates the sun's energy onto a pot for cooking. A cooker with a 1.2-m-diameter

Alekssandra [29.7K]

Answer:

26500 W/m²

Explanation:

Given that:

The diameter of the dish d = 1.2 m

Assuming the Solar power P capture by the dish = 1300 W

The surface area of the pot is calculated by using the formula:

$= \pi r^2$

$\pi \dfrac{d^2}{4}$

where; the diameter = 25 cm

Area = $\pi \dfrac{d^2}{4}$

Area = $\pi \dfrac{0.25^2}{4}$

Area = 0.049 m²

The intensity is calculated by using the formula

I = power/area

I = 1300/0.049

I = 26530.6 W/m²

I ≅ 26500 W/m²

3 0

3 years ago

If a ball is dropped into a very viscous liquid it will

Dafna1 [17]

It will go to the bottom of the liquid very slowly. Good Luck!

7 0

3 years ago

At which point is potential energy greatest?

LuckyWell [14K]

Answer:

when the most energy is stored

8 0

2 years ago

2. Consider a conical pendulum with a bob of mass m = 77.0 kg on a string of length L = 10.0 m that makes an angle of ???? 3.00°

bekas [8.4K]

Explanation:

It is given that,

The mass of bob, m = 77 kg

Length of the string, L = 10 m

Angle made by the string with the vertical, $\theta=3^{\circ}$

(a) Let T is the force exerted by the string on the pendulum. At equilibrium,

$T\ cos\theta=mg$

$T=\dfrac{mg}{cos\theta}$

$T=\dfrac{77\times 9.8}{cos(3)}$

T = 755.63 N

The horizontal component of the force is given by,

$T_H=T\ sin\theta$

$T_H=755.63\ sin(3)=39.54\ N$

The vertical component of the force is given by,

$T_V=T\ sin\theta=mg$

$T_V=754.59\ N$

(b) Let a is the radial acceleration of the bob. It can be calculated as :

$a=\dfrac{T_H}{m}$

$a=\dfrac{39.54\ N}{77\ kg}$

$a=0.51\ m/s^2$

Hence, this is the required solution.

6 0

3 years ago

Convert this number to standard notation: 1.4 x 10^-2*

Marysya12 [62]

Answer:

0.014

Explanation:

here

1.4 x 10^-2

=0.014

may this help

6 0

3 years ago