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Lisa [10]
3 years ago
8

2. Have someone hold the mirror for you, slowly move at least 3 m away from the it.

Chemistry
1 answer:
Ahat [919]3 years ago
3 0

Answer: Slowly move at least 3 m away from the side mirror. Observe your image as you ... Compare the images formed in different mirrors. ... but if i stand 3m away, even though there is no light, it reflects the other material it can ... is transparent so you cannot see yourself much in the mirror, that is my observation.

Explanation:

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Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

= 14.364 L

As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

= 9939.888 g

Hence, mass of 3.8 gal of the gasoline is 9939.888 g.



6 0
3 years ago
Which of the following is a source of water pollution?
Mashutka [201]
What are " of the following"? 

4 0
2 years ago
Read 2 more answers
What is the electronic structure of carbon
horsena [70]

Answer:

[He] 2s2 2p2

Explanation:

5 0
3 years ago
Define density and mass
KengaRu [80]

<u>density</u> is a measure of mass per volume. <u>mass</u> is both a property of a physical body and a measure of its resistance to acceleration.

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6 0
3 years ago
The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i
antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC

c = specific heat capacity of gold = 0.1291joules/gram^oC

m = mass of gold =15.71 g

Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram

Heat gained by gold = 2093.0621 Joules + 997.585 Joules

=3090.6471 joules

6 0
2 years ago
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