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Morgarella [4.7K]
3 years ago
14

When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an ____.

Chemistry
1 answer:
jonny [76]3 years ago
7 0
Carboxylic acid...........
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Benzophenone has a normal freezing point of +48.1 oC, with freezing point depression constant Kfpt = − 9.78 oC/m. A 0.1500 molal
Neporo4naja [7]

Answer:

i = 2.79

Explanation:

The excersise talks about the colligative property, freezing point depression.

Formula to calculate the freezing point of a solution is:

Freezing point of pure solvent - Freezing point of solution = m . Kf . i

Let's replace data given. (i = Van't Hoff factor, numbers of ions dissolved in solution)

48.1°C - 44°C = 0.15 m . 9.78°C/m . i

4.1°C / (0.15 m . 9.78°C/m) = i

i = 2.79

In this case, numbers of ions dissolved can decrease the freezing point of a solution, which is always lower than pure solvent.

3 0
3 years ago
True or false? In giant covalent structures the atoms form strong bonds by sharing electrons.
schepotkina [342]

Answer:

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6 0
2 years ago
The balance of the following equations
myrzilka [38]
A. 6 NaOH   +  2(NH4)3 PO4  ----->  2Na PO4  +  6H2O  +   6NH3

b. C2 H6 O  + 3O2  ---->   2CO2  +  3H2O
5 0
3 years ago
Heat energy is transferred on Earth by the processes of convection, conduction, and radiation. How does heat energy cause materi
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The isomerization of methylisonitrile to acetonitrile (CH3NC(g) ???? CH3CN) is first order in CH3NC. The rate constant for the r
Hoochie [10]

Answer:

The half life is     H_{1/2}= 7333.3sec

Explanation:

   The half life of a first order  reaction is mathematically represented as

                          H_{1/2} = \frac{0.693}{Rate Constant }

 Substituting   9.45 * 10^{-5}s^{-1}  for the rate constant

                         H_{1/2} = \frac{0.693}{9.45*10^{-5}}

                                 H_{1/2}= 7333.3sec

5 0
3 years ago
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