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dezoksy [38]
1 year ago
8

3. A lab technician is preparing urea broth. It should be sterilized by filtration, he autoclaves it instead, just like he does

for any other media. The high temperature of the autoclave causes the urea to break down. What color is the sterile urea broth when it comes out of the autoclave? but rstroedave tocave.
Chemistry
1 answer:
Andreas93 [3]1 year ago
5 0

<u>Urea get decomposed during autoclaving, because it is volatile. It is filter </u><u>sterilized </u><u>and added aseptically to your </u><u>autoclave media.</u>

Can urea be autoclaved?

  • Urea get decomposed during autoclaving, because it is volatile.
  • It is filter sterilized and added aseptically to your autoclave media.

What is autoclave sterilization?

  • In medical and laboratory settings, an autoclave is used to sterilise waste and lab supplies.
  • Heat is used in the autoclave sterilisation process to eliminate bacteria and spores. Pressurized steam provides the heat.

What is filter sterilization?

  • By using filtering, it is possible to exclude organisms based on their size. There are many different kinds of filtration methods, but membrane filtration is utilised to sterilise a system.
  • Contaminants that are larger than the pore size are captured by membrane filtration on the membrane's surface.

Learn more about autoclave media.

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Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

p_i=X_i\times p_T

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So,

p_i=\frac{n_i}{n_T}\times p_T

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p_i = partial pressure of gas

X_i = mole fraction of gas

p_T = total pressure of gas

n_i = moles of gas

n_T = total moles of gas

The balanced decomposition of ammonia reaction will be:

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Now we have to determine the partial pressure of N_2 and H_2

p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T

Given:

n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg

and,

p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T

Given:

n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg

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log (2.27/6.5) / log (1/2) = n = 1.52 half lives

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