Answer:

Explanation:
Given that,
Mass of the sample, m = 275 g
It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.
We need to find the specific heat of the metal. The heat required by a metal sample is given by :

c is specific heat of the metal

So, the specific heat of metal is
.
Answer : The mass of
occupy 30.3 L under the same conditions will be, 24.9 grams.
Explanation :
First we have to calculate the moles of 

Now we have to calculate the moles of
in 30.3 L by using Avogadro's law.
Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

or,

where,
= initial volume of gas = 6.21 L
= final volume of gas = 30.3 L
= initial moles of gas = 0.16 mol
= final temperature of gas = ?
Now put all the given values in the above equation, we get:


Now we have to calculate the mass of 

Molar mass of
= 32 g/mol

Therefore, the mass of
occupy 30.3 L under the same conditions will be, 24.9 grams.
M₁ *V₁ = M₂ * V₂
12.0 * V₁ = 6.0 * 500.0
12.0 V₁ = 3000
V₁ = 3000 / 12.0
V₁ = 250 mL
hope this helps!
Magma is made of molten rock. Melted of molten rock. Answer is rock.