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Andrej [43]
3 years ago
15

What effect doeshybridization have on boods,​

Chemistry
1 answer:
Alchen [17]3 years ago
3 0
Hybridisation influences the bond length and bond enthalpy strength in organic compounds. The sp hybrid orbital contains more s character and hence it is closer to its nucleus and forms shorter and stronger bonds than the sp3 hybrid orbital.
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Earth revolving around the sun, you walking down the street, and molecules moving in space all have
Ann [662]

Answer:

B. Kinetic energy

Explanation:

moving is kinetic, potential is inside a body  

6 0
4 years ago
An inflated balloon contains X air molecules.After some time the volume of the balloon is found to be the half at the same tempe
astra-53 [7]

<u>Answer:</u>

(a): The balloon will contain \frac{X}{2} number of molecules now.

(b): The gas law associated with this is Avogadro's law.

<u>Explanation:</u>

Avogadro's law states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature

Mathematically,

V\propto n                   (At constant pressure and temperature)

OR

\frac{V_1}{n_1}=\frac{V_2}{n_2}               .....(1)

where,

V_1\text{ and }n_1 = Initial volume and number of moles

V_2\text{ and }n_2 = Final volume and number of moles

We are given:

V_2=\frac{V_1}{2}

Putting values in equation 1, we get:

\frac{V_1}{n_1}=\frac{V_1}{2\times n_2}\\\\n_2=\frac{n_1}{2}

(a):

If n_1 number of moles of gas contains X number of molecules

So, \frac{n_1}{2} number of moles of gas will contain = \frac{X}{n_1}\times {n_1}{2}=\frac{X}{2} number of molecules

Hence, the balloon will contain \frac{X}{2} number of molecules now.

(b): The law used is Avogadro's law.

8 0
3 years ago
1. Used as a solvent
Yanka [14]

Answer:

1. Used as a solvent - CH3OH

2. The major constituent of natural gas -

CH4

3. Vinegar when in a diluted form - CH3COOH

4. Used in the manufacture of polyethylene plastic

C2H4

Hope this helps.

4 0
4 years ago
What is the yield of uranium from 2.50 kg U3O8?
mr_godi [17]

Answer: Thus the yield of uranium from 2.50 kg U_3O_8 is 2.12 kg

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number (6.023\times 10^{23}) of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}

moles of U_3O_8=\frac{2.50\times 1000g}{842g/mol}=2.97mol    (1kg=1000g)

As 1 mole of U_3O_8 contains = 3 moles of U

2.97 mole of U_3O_8 contains = \frac{3}{1}\times 2.97=8.91moles moles of U

Mass of Uranium=moles\times {\text {Molar mass}}=8.91mol\times 238g/mol=2120g=2.12kg  

 ( 1kg=1000g)

Thus the yield of uranium from 2.50 kg U_3O_8 is 2.12 kg

8 0
3 years ago
How many molecules in 11 grams of CO2?
yawa3891 [41]

Answer:

1095.62

Explanation:

5 0
3 years ago
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