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Andrej [43]
2 years ago
15

What effect doeshybridization have on boods,​

Chemistry
1 answer:
Alchen [17]2 years ago
3 0
Hybridisation influences the bond length and bond enthalpy strength in organic compounds. The sp hybrid orbital contains more s character and hence it is closer to its nucleus and forms shorter and stronger bonds than the sp3 hybrid orbital.
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The image shows a molecular model of a compound using balls and sticks. Each ball is an atom and each stick is a bond. If you we
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Hi , the answers must be part B
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In the hot climate, human bodies had to adapt by increasing the number of ____________ on the skin to cool off the body.
irga5000 [103]
D none of the above
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2 years ago
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If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered un
Murrr4er [49]

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

  • As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol

  • Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol

  • Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

8 0
3 years ago
A chemist prepares a solution of sodium thiosulfate (Na2S203) by measuring out 110.g of sodium thiosulfate into a 350. mL volume
forsale [732]

Answer:

1.99 M

Explanation:

The molar mass of sodium thiosulfate (solute) is 158.11 g/mol. The moles corresponding to 110 grams are:

110 g × (1 mol/158.11 g) = 0.696 mol

The volume of solution is 350 mL = 0.350 L.

The molarity of sodium thiosulfate is:

M = moles of solute / liters of solution

M = 0.696 mol / 0.350 L

M = 1.99 M

5 0
3 years ago
Of the metals pb hg na and mg which will not spontaneously donate electrons to copper in solution
marta [7]

Answer : Hg (Mercury)


Explanation : In the given series of elements Na falls after the Cu in the reactivity series, for Pb it also falls after Cu, and for Mg it is the same.


Only Hg which is mercury can spontaneously donate its electrons to copper in the solution because it falls before Cu in the reactivity/activity series.

3 0
3 years ago
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