Answer:
1C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)
Explanation:
In general equation combustions where all carbon produce CO₂ and all hydrogen H₂O we must begin the balance with these two species:
_C₆H₁₂O₆(s) + _O₂(g) → _CO₂(g) + _H₂O(l)
If sugar is 1, CO₂ and H₂O must be:
1C₆H₁₂O₆(s) + _O₂(g) → 6CO₂(g) + 6H₂O(l)
Thus, C and H are balanced. In the right side we have 12 oxygen from CO₂ + 6 oxygen from H₂O = 18 oxygen
In the left there are 6, thus, O₂ must provide 12 oxygens, thus:
<h3>
1C₆H₁₂O₆(s) +
6O₂(g) →
6CO₂(g) +
6H₂O(l)</h3>
And this is the balanced reaction
<u>Answer:</u> The molality of the solution is 0.1 m.
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute = 27.1 g
= Molar mass of solute = 27.1 g/mol
= Mass of solvent = 100 g
Putting values in above equation, we get:
Hence, the molality of the solution is 0.1 m.
Answer:
‑297 degrees Fahrenheit (‑183 degrees Celsius).
Explanation:
