Water and sodium oxide have different properties because of their nature as explained below.
<h3><u>Explanation:</u></h3>
Sodium oxide is a oxide of metallic sodium, while water is an oxide of hydrogen. So sodium oxide is a metallic oxide, while water is a non metallic oxide. Sodium oxide is a basic oxide, while water is neutral. As state of matter is concerned, sodium oxide is solid in normal room temperature, while water is liquid in normal room temperature. Water is a polar covalent molecule with partial charges on oxygen, but sodium oxide is an ionic molecule.
So all these factors contribute to very different properties of both sodium oxide and water.
The outcome of a experiment is the result
Answer:
The charge of the purple circles should be positive because they represent the nuclei.
Explanation:
According to Boyle's Law, P1V1 = P2V2
where P1 and V1 are initial pressure and volume respectively. P2 and V2 are final pressure and volume receptively.
Given: P2 = 4 P1 and V1 = 10.0l
∴ V2 = 2.5 l
Answer: Final volume of system is 2.5 l
Answer:
Explanation:
Hello,
In this case, the Boyle's is mathematically defined via:
Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:
We can compute the new pressure:
Which means the pressure is increased by a factor of four.
Regards.
