The amino acids are the molecules where we can found the carboxyl group (-
), amino group (-
), hydrogen atom (H) and a residual R-group. On the structure of the residual R-group the name of the amino acid depends. Like if R is hydrogen (H) the amino acid is alanine; If R- group is a phenyl group i.e. 
, the compound is called phenyl alanine. The structure of the general amino acid skeleton can be shown as-
Answer:
The answer is no. C. Rate =[A] [B]
The synthesis of
Methyl Phenyl Ether is shown below,
The synthesis takes place in two steps,
Step 1: Formation of Sodium Phenoxide: Phenol being more acidic than Alcohols with
pKa ≈ 10 can loose its proton attached to oxygen atom, as the resulting phenoxide ion is stabilized by resonance. Therefore, when phenol is treated with NaOH (bBase) it looses proton and forms Sodium Phenoxide.
Step 2: Formation of Methyl Phenyl Ether: The Phenoxide ion formed in first step when treated with Dimethyl Sulfate produces Methyl Phenyl Ether through a
Williamson's Ether synthesis Reaction. Dimethyl sulfate is a well known alkylating agent when treated with phenols, thiols and amines. Dimethyl sulfate readily transfers the methyl group and forms NaSO₄CH₃.
The reaction is as follow,
Answer:
Its particles are evenly distributed.
Explanation:
Solutions are homogenous mixtures of solutes and solvents. In a solution the solute particles are evenly distributed in the solvent.
Here are some characteristics of solutions:
- The size of the particles is small
- The particles do not settle on standing
- The particles pass through ordinary filter papers
- The particles pass through permeable membranes
- The particles are not visible with microscope or the naked eyes.
- They are clear and may have a color.
Answer:
0.55 g of Cu can produced by this decomposition
Explanation:
Let's think the reaction of decomposition:
2CuO → 2Cu + O₂
Ratio is 2:2. 2 moles of CuO can decompose into 2 moles of Cu and 1 mol of oxygen.
Let's convert the mass of oxyde to moles → 0.695 g. 1 mol/ 79.55 g =
8.74×10⁻³ moles
8.74×10⁻³ mol of CuO decompose to 8.74×10⁻³ moles of Cu
Let's find out the mass → 8.74×10⁻³ mol . 63.55 g/1mol = 0.55 g
