Answer:
1. 0.240 mole of magnesium ion, Mg^2+
2. 0.48 mole of chloride ion, Cl^-
Explanation:
We'll begin by writing the balanced dissociation equation for magnesium chloride. This is given below:
MgCl2(aq) —> Mg^2+(aq) +2Cl^-(aq)
1. Determination of the number of mole of magnesium ion, Mg^2+ obtained from the dissolution 0.240 mol of magnesium chloride, MgCl2 in water. This is illustrated below:
From the balanced equation above,
1 mole of MgCl2 produced 1 mole of Mg^2+.
Therefore, 0.240 mole of MgCl2 will also produce 0.240 mole of Mg^2+.
Therefore, 0.240 mole of magnesium ion, Mg^2+ is produced.
2. Determination of the number of mole of chloride ion, Cl^- obtained from the dissolution 0.240 mol of magnesium chloride, MgCl2 in water. This is illustrated below:
From the balanced equation above,
1 mole of MgCl2 produced 2 moles of Cl^-.
Therefore, 0.240 mole of MgCl2 will produce = (0.240 x 2) = 0.48 mole of Cl^-.
Therefore, 0.48 mole of chloride ion, Cl^- is produced.
