First let us assign variables,
d = distance travelled
t = time it took
v = velocity of the commercial airline
In linear physics, the equation for velocity is given as:
v = d / t
Rewriting for d:
d = v t
We know that the distance to and from south America are equal
therefore:
d1 (going) = d2 (return)
Let us say that velocity of air is v3. Since going to South
America, the wind is against the direction of the plane and the return trip is
the opposite, therefore:
(v1 - v3) t1 = (v1 + v3) t2
(v1 – v3) 4 = (v1 + v3) 3.53
4 v1 – 4 v3 = 3.53 v1 + 3.53 v3
0.47 v1 = 7.53 v3
v1 = 16.02 v3
Since we also know that:
(v1 - v3) t1 = 784
(16.02 v3 – v3) * 4 = 784
60.085 v3 = 784
v3 = 13.05 mph
Therefore the speed of the plane in still air, v1 is:
v1 = 16.02 * 13.05
<span>v1 = 209.03 mph (ANSWER)</span>
<span> </span>
Answer:
660V
Explanation:
V=IR
V=11×60
=660V
hope this helps
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Answer:
- <u>2.79 N</u>
- <u>8.34 N</u>
- <u>Watermelon</u>
Explanation:
<u>Weight of soccer ball</u>
- Weight = mass (in kg) × gravitational force
- Weight = 284 x 10⁻³ x 9.81
- Weight = 0.284 x 9.81
- Weight = <u>2.79 N</u> (approximately)
<u>Weight of watermelon</u>
- Weight = mass (in kg) x gravitational force
- Weight = 850 x 10⁻³ x 9.81
- Weight = 0.85 x 9.81
- Weight = <u>8.34 N</u> (approximately)
As the <u>watermelon</u> has more weight, it will hit the ground first.
Answer:
The correct option is;
Technician A only
Explanation:
Leaks in the cooling system parts such as the radiator cap can be tested with a pressure operated hand pump by attaching the pump cap to the pump with an adaptor and apply pressure enough for there to be a release of pressure at the cap.
The pressure added to the system should be maintained for up to two minutes. If the pressure drops quicker, then there is likely to be leaks in the system
The freezing and boiling point of the coolant is measured with an antifreeze tester which carries the appropriate apparatus to measure the coolants freezing and boiling points.
To solve this problem it is necessary to apply the concepts related to
conservation of energy, for this case manifested through work and kinetic energy.


Where,
F= Force (Frictional at this case
)
d= Distance

Where,
m = mass
v = velocity
Equation both terms,




Replacing with our values we have that


Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m