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N76 [4]
3 years ago
12

Yield management is the process of understanding, anticipating and influencing consumer behavior in order to maximize yield or p

rofits from a fixed, perishable resource (such as airline seats or hotel room reservations or advertising inventory)
The Super Bowl is right around the corner and Gowgem Hotels is aquiver with
anticipation. They'd like to price their rooms at their three city locations, next to the stadium, near the airport, and in the suburbs, as high as possible but still achieve 100% occupancy. The approach they should take to this opportunity is a yield management.
Physics
1 answer:
Inessa [10]3 years ago
4 0

This question is incomplete, here´s the complete question.  

The super bowl is right around the corner and Bowen hotels is aquiver with anticipation. They'd like to price their rooms at their three city locations, next to the stadium, near the airport, and in the suburbs, as high as possible but still achieve 100% occupancy. The approach they should take to this opportunity is :

- Yield management

- 360 units per month

- A chase production approach

- A tiered workforce

Answer: Yield management

Explanation:

Yield management, also called revenue management, is a variable pricing strategy usually applied in the hospitality business, such as air travel and several tourism-related enterprises. Yield management aims to produce maximum revenue from a fixed, perishable resource, like plane tickets, hotel room bookings, or advertising inventory. The goal is to obtain the highest possible profit by offering the right price at the right time.

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Question 4 (1 point)
irga5000 [103]

Answer:

ω₁ = 8 rad/s

Explanation:

Assuming

1) the clay sticks to the disc we can apply conservation of angular momentum

2) That the disc moment of inertia is 1.5 kg•m²

Initial angular momentum = L = I₀ω₀ = 1.5(14) = 21 kg•m²/s

After the clay joins the party, the moment of inertia is

I₁ = 1.5 + 0.5(1.5²) = 2.625 kg•m²

21 = 2.625ω₁

ω₁ = 8 rad/s

6 0
2 years ago
A paper airplane is thrown westward at a rate of 6 m/s. The wind is blowing at 8 m/s towards the north. Which of the following d
Andrew [12]

since airplane is thrown towards west with speed 6 m/s

while air is blowing with speed 8 m/s towards north

so here the net speed of air plane will be the resultant of airplane speed and wind speed always

SO here we can say it would be a combination of vector along west with must be of length 6 m/s and other vector is towards north with is of length 8 m/s

so correct answer must be 1st option


5 0
3 years ago
What is the net force required to accelerate a 16 kg box at a rate or 1.4 m/s^2
stich3 [128]
You can use Newton's Second Law which states:
\sum \vec{F} = m\vec{a}

Plug in given information:
\sum \vec{F}=16(1.4) = 22.4N

This is closest to option b which is your answer.
8 0
3 years ago
How are stars formed and classified?
Romashka-Z-Leto [24]
Stars form from an accumulation of gas and dust, which collapses due to gravity and starts to form stars. Stars are typically classified by their spectrum in what is known as the Morgan-Keenan or MK system.
6 0
3 years ago
A 2kg block has 70J of KE. It then travels 1.5 meters up a hill. As it travels up the hill friction does -12J of work on the blo
Dima020 [189]

Answer:

v = 5.34[m/s]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the sum of the mechanical energy in the initial state plus the work on or performed by a body must be equal to the mechanical energy in the final state.

Mechanical energy is defined as the sum of energies, kinetic, potential, and elastic.

E₁ = mechanical energy at initial state [J]

E_{1}=E_{pot}+E_{kin}+E_{elas}\\

In the initial state, we only have kinetic energy, potential energy is not had since the reference point is taken below 1.5[m], and the reference point is taken as potential energy equal to zero.

In the final state, you have kinetic energy and potential since the car has climbed 1.5[m] of the hill. Elastic energy is not available since there are no springs.

E₂ = mechanical energy at final state [J]

E_{2}=E_{kin}+E_{pot}

Now we can use the first statement to get the first equation:

E_{1}+W_{1-2}=E_{2}

where:

W₁₋₂ = work from the state 1 to 2.

E_{k}=\frac{1}{2} *m*v^{2} \\

E_{pot}=m*g*h

where:

h = elevation = 1.5 [m]

g = gravity acceleration = 9.81 [m/s²]

70 - 12 = \frac{1}{2}*2*v^{2}+2*9.81*1.5

58 = v^{2} +29.43\\v^{2} =28.57\\v=\sqrt{28.57}\\v=5.34[m/s]

4 0
3 years ago
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