1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
N76 [4]
4 years ago
12

Yield management is the process of understanding, anticipating and influencing consumer behavior in order to maximize yield or p

rofits from a fixed, perishable resource (such as airline seats or hotel room reservations or advertising inventory)
The Super Bowl is right around the corner and Gowgem Hotels is aquiver with
anticipation. They'd like to price their rooms at their three city locations, next to the stadium, near the airport, and in the suburbs, as high as possible but still achieve 100% occupancy. The approach they should take to this opportunity is a yield management.
Physics
1 answer:
Inessa [10]4 years ago
4 0

This question is incomplete, here´s the complete question.  

The super bowl is right around the corner and Bowen hotels is aquiver with anticipation. They'd like to price their rooms at their three city locations, next to the stadium, near the airport, and in the suburbs, as high as possible but still achieve 100% occupancy. The approach they should take to this opportunity is :

- Yield management

- 360 units per month

- A chase production approach

- A tiered workforce

Answer: Yield management

Explanation:

Yield management, also called revenue management, is a variable pricing strategy usually applied in the hospitality business, such as air travel and several tourism-related enterprises. Yield management aims to produce maximum revenue from a fixed, perishable resource, like plane tickets, hotel room bookings, or advertising inventory. The goal is to obtain the highest possible profit by offering the right price at the right time.

You might be interested in
A pair of scissors is a complex machine. what simple machines make up a pair of scissors?
vova2212 [387]
2 blades and a securing bolt.
4 0
3 years ago
Read 2 more answers
If the clock runs slow and loses 15 s per day, how should you adjust the length of the pendulum?
Shkiper50 [21]

Answer:

L= 1 m,   ΔL = 0.0074 m

Explanation:

A clock is a simple pendulum with angular velocity

         w = √ g / L

Angular velocity is related to frequency and period.

         w = 2π f = 2π / T

We replace

        2π / T = √ g / L

        T = 2π √L / g

We will use the value of g = 9.8 m / s², the initial length of the pendulum, in general it is 1 m (L = 1m)

With this length the average time period is

           T = 2π √1 / 9.8

           T = 2.0 s

They indicate that the error accumulated in a day is 15 s, let's use a rule of proportions to find the error is a swing

           t = 1 day (24h / 1day) (3600s / 1h) = 86400 s

         e= Δt = 15 (2/86400) = 3.5 104 s

The time the clock measures is

           T ’= To - e

           T’= 2.0 -0.00035

           T’= 1.99965 s

Let's look for the length of the pendulum to challenge time (t ’)

           L’= T’² g / 4π²

           L’= 1.99965 2 9.8 / 4π²

           L ’= 0.9926 m

Therefore the amount that should adjust the length is

           ΔL = L - L’

           ΔL = 1.00 - 0.9926

           ΔL = 0.0074 m

8 0
3 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
MEASUREMENT
lubasha [3.4K]

Answer:

You would need to type the numbers in the question or you could have added a picture but you didn't so there is no way to answer this question. Have a nice day!

5 0
3 years ago
A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back
Kobotan [32]

Answer:

a) 5 m/s

b) 17.8542 m/s

c) 24.7212 m/s

0.229

Explanation:

t = Time taken

u = Initial velocity = 5 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=5-9.81\times t\\\Rightarrow \frac{-5}{-9.81}=t\\\Rightarrow t=0.51 \s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=5\times 0.51+\frac{1}{2}\times -9.81\times 0.51^2\\\Rightarrow s=1.27\ m

So, the stone would travel 1.27 m up

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.27+0^2}\\\Rightarrow v=5\ m/s

Velocity as the rock passes through the original point is 5 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 1.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.27\times 2}{9.81}}\\\Rightarrow t=0.51\ s

Time taken to reach the original point is 0.51+0.51 = 1.02 seconds

So, total height of the rock would fall is 30+1.27 = 31.27 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 16.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{16.27\times 2}{9.81}}\\\Rightarrow t=1.82\ s

Time taken by the stone to reach 15 m above the ground is 1.82+0.51 = 2.33 seconds

v=u+at\\\Rightarrow v=0+9.81\times 1.82\\\Rightarrow v=17.8542\ m/s

Speed of the ball at 15 m above the ground is 17.8542 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 31.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{31.27\times 2}{9.81}}\\\Rightarrow t=2.52\ s

v=u+at\\\Rightarrow v=0+9.81\times 2.52\\\Rightarrow v=24.7212\ m/s

Speed of the stone just before it hits the street is 24.7212 m/s

F = Force

m = Mass = 100 kg

g = Acceleration due to gravity = 9.81 m/s²

s = Displacement = 4 km = 4000 m

P = Power = 1 hp = 745.7 Watt

t = Time taken = 20 minutes = 1200 seconds

μ = Coefficient of sliding friction

F = μ×m×g

⇒F = μ×100×9.81

W = Work done = F×s

P = Work done / Time

⇒P = F×s / t

745.7=\frac{\mu \times 981\times 4000}{1200}\\\Rightarrow \mu=\frac{747.5\times 1200}{981\times 4000}\\\Rightarrow \mu=0.229

Coefficient of sliding friction is 0.229

8 0
3 years ago
Other questions:
  • High and low pressure areas leading to air movement happen when there are differences in
    15·2 answers
  • A very fine thread is placed between two glass plates on one side and the other side is touching to form a wedge. A beam of mono
    5·1 answer
  • In addition to National Electrical Code requirements, some areas have ___ requirements for energy conservation that also affect
    8·1 answer
  • You're driving down the highway late one night at 20 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
    15·1 answer
  • An object of 4 kg has a speed of 6 m/s and moves a distance of 8 m. What is its kinetic energy in joules.
    5·1 answer
  • Is there a way to see moon and the sun at once?
    7·2 answers
  • What happens to the metals electrical conductivity when the temperature hits up​
    7·1 answer
  • Create 2 models, please.
    8·1 answer
  • Where would a roller coaster have the same speed
    12·2 answers
  • The first formant of your vocal system can be modeled as the resonance of an open-closed tube, the closed end being your vocal c
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!