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sineoko [7]
3 years ago
11

True or False: Exercise is an underrated stress reliever and can be used to 25

Physics
2 answers:
Andreyy893 years ago
5 0

Answer:

I think it is true I'm not saying it is but if you get another person who says its true say true

Explanation:

uranmaximum [27]3 years ago
3 0
I believe the answer is true
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An example of when total internal reflection occurs is when all the light passing from a region of higher index of refraction to
Amiraneli [1.4K]

Answer:

is reflected back into the region of higher index

Explanation:

Total internal reflection is a phenomenon that occurs when all the light passing from a region of higher index of refraction to a region of lower index is reflected back into the region of higher index.

According to Snell's law, refraction of ligth is described by the equation

n_1 sin \theta_1 = n_2 sin \theta_2

where

n1 is the refractive index of the first medium

n2 is the refractive index of the second medium

\theta_1 is the angle of incidence (in the first medium)

\theta_2 is the angle of refraction (in the second medium)

Let's now consider a situation in which

n_1 > n_2

so light is moving from a medium with higher index to a medium with lower index. We can re-write the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

Where \frac{n_1}{n_2} is a number greater than 1. This means that above a certain value of the angle of incidence \theta_1, the term on the right can become greater than 1. So this would mean

sin \theta_2 > 1

But this is not possible (the sine cannot be larger than 1), so no refraction occurs in this case, and all the light is reflected back into the initial medium (total internal reflection). The value of the angle of incidence above which this phenomen occurs is called critical angle, and it is given by

\theta_c =sin^{-1}(\frac{n_2}{n_1})

8 0
3 years ago
The MSDS for chloroform indicates that it is a clear liquid that has a pleasant smell and substantial vapor pressure. People sho
Norma-Jean [14]

Answer:

The correct option is the third option

Explanation:

Firstly, it must be noted that chemicals/reagents that are sensitive to sunlight are stored in dark/amber container in the laboratory. Hence, the chloroform can only be found in an amber/dark bottle.

Also, reagents/chemicals that release poisonous/offensive gases are handled in the fume cupboard in the laboratory. Thus, If Malik is going to pour the chloroform, he should pour it in a fume cupboard to avoid inhaling it because of the toxicity of it's vapor.

From the above explanation, it can be deduced that <u>Malik should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour</u>.

8 0
3 years ago
A locomotive is pulling 8 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (wi
nikitadnepr [17]

Answer:106560 N

Explanation:

Given

Let Tension between  2 and 3 car be T_{23} and between 3 &4 is T_{34}

T_{23}-T_{34}=ma

mass of freight car =37,000 kg

acceleration of car=0.48 m/s^2

T_{34} is accelerating all freights behind 3

therefore

T_{34}=5\times ma

T_{34}=5\times 37000\times 0.48=88,800 N

Thus

T_{23}=T_{34}+ma

T_{23}=88,800+37000\times 0.48=88,800+17,760=106560 N

4 0
3 years ago
A mass of gas under constant Pressure occupies a volume of 0.5 M3 At a temperature of 20゚C using the formula for Cubic expansion
MAVERICK [17]

To answer this question, we must use the equation for the volumetric expansion of gases at constant pressure. This equation is given by:

V=V_{0}(1 + \alpha(T_{2}-T_{1}))

We know:

V_{0} is the initial volume = 0.5 m ^ 3

ΔT is the temperature change = 45 ° -20 ° = 25 °

\alpha is the coefficient of gas expansion and is equal to 1/273

Then the final volume of the gas is:

V=0.5*(1+\frac{1}{273}*25)

V=0.546m^ 3

7 0
3 years ago
laser light sent through a double slit produces an interference pattern on a screen 3.0 m from the slits. If the eighth order ma
Xelga [282]

Solution :

Given the laser light which is sent through the double slit produces an interference pattern on the screen placed 3  meters from the slits.

The 8th order maximum occurs at angle = 12

So,

$8^{th} \text{ order maxima} = d \sin \theta = m \lambda$      , m = 8

$d = \frac{8 \lambda}{\sin 12}$

$\frac{\lambda}{d}= \frac{\sin 12}{8}$

$3^{rd} \text{ order maxima}= d \sin \theta_2 = m_2 \lambda$

$\sin \theta_2 = \frac{m_2 \lambda}{d}=\frac{3 \lambda}{d}$ $=0.75\ {\sin 12}$

$\theta_2 = \sin^{-1}\left(0.75\ \sin 12\right)$

   $ = \sin^{-1}\left(0.155)$

   $=8.91^\circ$

8 0
3 years ago
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