Answer:
1.) 1620 km/h^2
2.) 2.7 km
Explanation:
1.) Given that the car start from rest. The initial velocity U will be equal to zero. That is,
U = 0.
Final velocity V = 54 km/h
Time t = 2 minute = 2/60 = 1/30 hour
Acceleration a will be change in velocity per time taken. That is,
a = ( V - U )/ t
Substitute V, U and t into the formula
a = 54 ÷ 1/30
a = 54 × 30 = 1620 km/h ^2
2.) Distance travelled S by the car during the time can be calculated by using the 2nd equation of motion.
S = Ut + 1/2at^2
Substitute all the parameters into the formula
S = 54 × 1/30 + 1/2 × 1620 × (1/30)^2
S = 54/30 + 810 × 1/900
S = 54/30 + 810/900
S = (1620+810)/900
S = 2430/900
S = 2.7 km.
Therefore, distance travelled by the car during this time is 2.7 km
Answer: 25Hz
Explanation:
Given that:
Wavelength (λ) = 0.4m (the distance between the peaks of a wave is known as wavelength)
Frequency F = ?
Speed of wave V = 10 m/s
The wave frequency is the number of cycles which the wave complete in one second. It is measured in hertz, and represented by the symbol F
So, apply the formula V = F λ
10m/s = F x 0.4m
F = 10m/s / 0.4m
F = 25Hz
Thus, the frequency of the wave is 25 Hertz.
Answer:
The strength of the field
Explanation:
The density of field lines of a field (e.g. gravitational field, or electric field) indicates the strength or magnitude of the field itself. In particular:
- The regions in which the field lines are closer to each other (more dense) are the regions where the field is stronger
- The regions where the field lines are more spread apart (less dense) are the regions where the field is weaker
For example, if we consider the electric field generated by a positive point charge, the electric field is radial (outwards from the charge) and the spacing between the lines increases as we move away from the charge: this means that the strength of the field increases as we move away from the charge.
We are given with
M = mass of planet
R = radius of circular trajectory of the satellite
ms = mass of the station
mm = mass of the meteorite
ms = 10 mm
R/2 = new orbit distance
The speed of the meteorite can be solved using the law of conservation of momentum
ms vs + mm vm = (ms + mm) v
Since the new orbit distance is half the original
v = 2 vs
Substitute and solve for vs
