To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.
Torque in a body is defined as,

And in angular movement like

Where,
F= Force
d= Distance
I = Inertia
Acceleration Angular
PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.

On the other hand we have the speed data expressed in RPM, as well


Acceleration can be calculated by



In the case of Inertia we know that it is equivalent to


Matching the two types of torque we have to,




PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,



Answer:
(D) 0.99 cm
Explanation:
Given that the radius of curvature of the mirror is 25 cm.
And another car is following which is behind the mirror of 20 m.

Focal length is half of the radius of curvature and it is negative for convex lens.
Now the mirror formula.

So,

Now
Magnification is,

So,

So, Height of the image

Therefore, the image height is 0.99 cm.
Pnet = Po + dgh
<span>Density of saltwater = 1030 kg/m^3. </span>
<span>Disregard the thickness. Assuming it's a circular window, then the area is pi(r^2). </span>
<span>d = 20 cm = 0.2 m </span>
<span>r = d/2 = 0.1 m </span>
<span>A = pi(r^2) </span>
<span>A = 3.14159265(.1^2) </span>
<span>A = 0.0314159265 m^2 </span>
<span>p = F/A </span>
<span>p = (1.1 x 10^6) / (0.0314159265) </span>
<span>p = 35,014,087.5 Pa </span>
<span>1 atm = 101,325 Pa </span>
<span>P = Po + dgh </span>
<span>h = (P - Po) / dg </span>
<span>h = (35,014,087.5 - 101,325) / (1030 x 9.81) </span>
<span>h = 3 455.23812 m </span>
<span>h = 3.5 km</span>
Period is 1/frequency
1/425 = 2.353ms