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3 years ago

How did the approximate speed

Physics

1 answer:

Setler [38]3 years ago

7 0

Answer:

i think this may help you

Explanation:

In an inelastic collision the total kinetic energy after the collision is not equal to the total ... If there are no net forces at work (collision takes place on a frictionless surface ... Momentum is equal to the product of mass and velocity. ... bodies before the collision is equal to the total kinetic energy of the bodies after the collision.

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A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th

madam [21]

Answer:

1.31498 kg

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

$mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg$

The mass of the block is 1.31498 kg

Time period is given by

$T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s$

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

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3 years ago

What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force in jou

BaLLatris [955]

Work done= 70 *9 = 63J

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4 years ago

Svetllana [295]

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2 years ago

A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?

Ainat [17]

Answer:

V = 5.83 m/s

Explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{2\times 35+10\times 0}{2+10}\\\\V=5.83\ m/s$

So, the velocity of the box after the collision is equal to 5.83 m/s.

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3 years ago

If mass is conserved during a nuclear reaction, then _____.

aleksley [76]

Then, the reaction does not have any kinetic energy

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4 years ago