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pav-90 [236]
3 years ago
7

How does the law of conservation of energy apply to machinesBased on the law of conservation of energy, how can we reasonably im

prove a machine’s ability to do work?
Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:

According,to the law of conservation of energy,the amount of energy in a closed system always stay constant. ... So,the amount of work output and other transformed energy is equal to the amount of energy inputs. • In this way,the conservation of energy is fulfilled by the machines.

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How is the q of an rlc parallel resonant circuit calculated?
notka56 [123]

Answer:

It is calculated by dividing Resistance, R, by Inductive reactance, XL.

Explanation:

Q is called the Q factor of a resonance circuit. In a parallel resonance circuit, it is calculated by finding the ratio of the power stored in the circuit to the power distributed in the circuit. It is a way of measuring the quality of a circuit or how effective the circuit is.

Q factor is the inverse in the resonance series circuit.

Q factor of a resonance parallel circuit,

<h3>Q = R/XL</h3>

R = Resistance

XL = Inductive reactance

3 0
3 years ago
Use the information from the graph to answer the question. What is the acceleration of the object
Art [367]

Answer:

-2.5 m/s²

Explanation:

The acceleration of a body is the change in it's velocity with time.

The change in velocity with time can be obtained as the slope of a velocity time graph ;

Acceleration = (change in velocity / change in time)

Taking the slope :

Change in Velocity = △y = y2 - y1

Change in time = △x = x2 - x1

(10, 15) ; (0, 40)

△y / △x = y2 - y1 / x2 - x1 = (40 - 15) / (0 - 10)

△y / △x = 25 / - 10 = - 2.5 m/s²

4 0
3 years ago
A 35-year-old patent clerk needs glasses of 50-cm focal length to read patent applications that he holds 25 cm from his eyes. Fi
Natali5045456 [20]

Answer:

28.57 cm

Explanation:

We are given that

Focal length,f=50 cm

Distance of application from his eyes,s=40 cm

\frac{1}{s}+\frac{1}{s'}=\frac{1}{f}

\frac{1}{40}+\frac{1}{s'}=\frac{1}{50}

\frac{1}{s'}=\frac{1}{50}-\frac{1}{40}=\frac{4-5}{200}

s'=\frac{200}{-1}=-200 cm

s=25 cm

Substitute the values

\frac{1}{25}-\frac{1}{200}=\frac{1}{f'}

\frac{8-1}{200}=\frac{1}{f'}

\frac{1}{f'}=\frac{7}{200}

f'=\frac{200}{7}=28.57 cm

6 0
3 years ago
" A body A moves with a speed 0.2l along straight path in a
choli [55]

Answer:

incomplete

Explanation:

8 0
3 years ago
Explain how a manufacturing business might participate in the ""resource disposal"" aspect of resource management.
LUCKY_DIMON [66]

Answer:

Resource disposal or waste disposal is a crucial aspect of resource management.

Businesses in the manufacturing sector must develop a model of operations that allows an endless loop of internal recycling of waste and or processing waste resources into commercial resources.

A good example would be when an abattoir processes the internal organs of cows and goats with some waste gotten from rice mill into can food for dogs and canines. Waste from this secondary process can either be converted into organic manure to be sold to farmers or processed further for consumption at carnivorous fish farms.

Cheers

3 0
3 years ago
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