How does the law of conservation of energy apply to machinesBased on the law of conservation of energy, how can we reasonably im
1 answer:
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Answer:
16.5 kwh and 59400 kJ.
Explanation:
kWh is a measure of energy that is equivalent to the power in kw times the number of hours the device worked.
In this case, it would be equal to:
1 kw also means 1kj of energy spent per second. With this, we calculate the amount of energy in kJ spent by the resistance:
0 = u^2 + 2*(-2)*9600
u^2 = 38400
u = 195.96 m/s