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grigory [225]
2 years ago
7

How did Niels Bohr create the Atomic theory

Physics
2 answers:
den301095 [7]2 years ago
7 0

Niels Bohr created the Atomic theory by combining Rutherford's description of the nucleus and Planck's theory about quanta.

<h3>What is Bohr's atomic theory?</h3>

This was proposed by Neil Bohr and talks about how electrons move in fixed orbitals and not anywhere in between and was able to explain that each orbit has a fixed energy.

He explained the various activities and processes which were happening inside an atom thereby deducing a picture of atomic structure such as the presence of the subatomic particles in the nucleus and how they are involved in a chemical reaction.

The structure was that of a planetary model in which the negatively charged electrons orbit a small, positively charged nucleus which is similar to the planets.

This is therefore the different processes and ways in which Bohr created his atomic theory.

Read more about Atomic theory here brainly.com/question/14973393

#SPJ1

qwelly [4]2 years ago
5 0

Niels  Bohr created the Atomic theory after studying the way glowing, hot hydrogen that gives off light.

<h3>How did Niels Bohr create the Atomic theory?</h3>

He developed the atomic model after studying the glowing of hot hydrogen that gives off light. When a light bulb is lit, it gives all the different wavelengths of the light. Niels Bohr proposed an atomic theory for the hydrogen atom, which is based on quantum theory. He says in this theory that Electrons move around an orbit of the nucleus , and If the electrons jump from a lower-energy orbit to a higher energy orbit, the energy is released in orbit in the form of radiation.

so we can conclude Niels Bohr created the Atomic theory after studying the way glowing, hot hydrogen that gives off light.

learn more about atomic theory here: brainly.com/question/4149596

#SPJ1

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Two bumper cars in an amusement park ride collide elastically as one approaches the other directly fromthe rear. Car A has a mas
zubka84 [21]

Answer:

a) The velocity of car B after the collision is 4.45 m/s.

The velocity of car A after the collision is 3.65 m/s.

b) The change of momentum of car A is - 370.45 kg · m/s

The change of momentum of car B is 370.45 kg · m/s

Explanation:

Hi there!

Since the cars collide elastically, the momentum and kinetic energy of the system do not change after the collision.

The momentum of the system is calculated adding the momenta of each car:

initial momentum = final momentum

mA · vA + mB · vB = mA · vA´ + mB · vB´

Where:

mA = mass of car A

vA = initial velocity of car A

mB = mass of car B

vB = initial velocity of car B

vA´= final velocity of car A

vB´ = final velocity of car B

Let´s replace with the data we have and solve the equation for vA´:

mA · vA + mB · vB = mA · vA´ + mB · vB´

435 kg · 4.50 m/s + 495 kg · 3.70 m/s = 435 kg · vA´ + 495 kg · vB´

3789 kg · m/s = 435 kg · vA´ + 495 kg · vB´

3789 kg · m/s - 495 kg · vB´ = 435 kg · vA´

(3789 kg · m/s - 495 kg · vB´)/435 kg = vA´

Let´s write this expression without units for a bit more clarity:

vA´= (3789 - 495 vB´)/435

The kinetic energy of the system is also conserved, then, the initial kinetic energy is equal to the final kinetic energy:

initial kinetic energy of the system = final kinetic energy of the system

1/2 · mA · vA² + 1/2 · mB · vB² = 1/2 · mA · (vA´)² + 1/2 · mB · (vB´)²

Replacing with the data:

initial kinetic energy = 1/2 · 435 kg · (4.50 m/s)² + 1/2 · 495 kg · (3.70)²

initial kinetic energy = 7792.65 kg · m²/s²

7792.65 kg · m²/s² = 1/2 · 435 kg · (vA´)² + 1/2 · 495 kg · (vB´)²

multiply by 2 both sides of the equation:

15585.3 kg · m²/s² =  435 kg · (vA´)² + 495 kg · (vB´)²

Let´s replace vA´ = (3789 - 495 vB´)/435

I will omit units for clarity in the calculation:

15585.3  =  435 · (vA´)² + 495 · (vB´)²

15585.3  =  435 · (3789 - 495 vB´)²/ 435² + 495 (vB´)²

15585.3 = (3789² - 3751110 vB´ + 245025 vB²) / 435 + 495 (vB´)²

multiply both sides of the equation by 435:

6779605.5 = 3789² - 3751110 vB´ + 245025 vB² + 215325 vB´²

0 = -6779605.5 + 3789² - 3751110 vB´ + 460350 vB´²

0 = 7576915.5 - 3751110 vB´ + 460350 vB´²

Solving the quadratic equation:

vB´ = 4.45 m/s

vB´ = 3.70 m/s (the initial velocity)

a) The velocity of car B after the collision is 4.45 m/s

The velocity of car A will be teh following:

vA´= (3789 - 495 vB´)/435

vA´= (3789 - 495 (4.45 m/s))/435

vA´ = 3.65 m/s

The velocity of car A after the collision is 3.65 m/s

b) The change of momentum of each car is calculated as the difference between its final momentum and its initial momentum:

ΔpA = final momentum of car A - initial momentum of car A

ΔpA = mA · vA´ - mA · vA

ΔpA = mA (vA´ - vA)

ΔpA = 435 kg (3.648387097 m/s - 4.50 m/s)  (I have used the value of vA´ without rounding).

ΔpA = - 370.45 kg · m/s

The change of momentum of car A is - 370.45 kg · m/s

ΔpB = mB (vB´ - vB)

ΔpB = 495 kg (4.448387097 m/s - 3.70 m/s) (I have used the value of vB´ without rounding).

ΔpB = 370.45 kg · m/s

The change of momentum of car B is 370.45 kg · m/s

I have used the values of the final velocities without rounding so we can notice that the change of momentum of both cars is equal but of opposite sign.

7 0
3 years ago
What is the unit of G in the F=Gm1m2/r^2​
kobusy [5.1K]


G
has the SI units
m
3
k
g
⋅
s
2
6 0
3 years ago
Read 2 more answers
When light passes from air into water at an angle of 60° from the normal, what is the angle of refraction? (40.6°)
matrenka [14]

Answer:

40.6°

Explanation:

5 0
3 years ago
Describe what would happen if anything to the mass and weight when you go to jupiter
Art [367]

If you were somehow magically transported to Jupiter, your mass
would not change, but your weight would become roughly 2.5 times
your Earth weight.

6 0
3 years ago
Read 2 more answers
3. What is the temperature if a 545-Hz sound wave has a wavelength of 0.651 m
KATRIN_1 [288]

Answer:

19.33°C

Explanation:

To find the value of T you use the following formula:

v=343+0.61T

v: speed of sound

To calculate v you use:

v=\lambda f

λ: wavelength = 0.651m

f:  = 545Hz

by replacing :

v=(0.651m)(545s^{-1})=354.79m/s

Finally, by replacing in the first formula you obtain:

354.79=343+0.61T\\\\T=19.33\°C

T = 19.33°C

7 0
3 years ago
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