W^2 = 2 A 8 where A is the angular acceleration.
(3w)^2 = 2 A R where R is the number of revolutions.
Note that you are asked for the additional revolutions.
Answer:
7500 m
Explanation:
The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.
We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so
d = 2L
In a time of

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:
(1)
where


, where L is the distance between the radar and the object
Re-arranging eq(1) and substituting, we find L:

Answer:
Minimize the elevation or jump distance
Explanation:
The only action that minimizes, the impact force is to reduce as much as possible the height of the jump, the dog, ie the height from the jump point of the building. Since at the time of the jump its speed will increase every second at the rate of 9 [m/ s], that is this low effect of the gravitational acceleration of 9 [m/s^2]

where:
vf = final velocity [m/s]
g = gravity [m/s^2]
h = elevation [m]
As we can see while there is higher height, at a higher speed will impact the ground.

- Initial velocity,u = -2 m/s
- Final velocity,v = -10 m/s
- Time taken, t = 4 seconds

Find the acceleration ( a ) .

We know that,

Substituting the values in the above formula, we get




Hence,the acceleration of a body is -2 m/s².
I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B