Tayler money ................... 320$
Estimated cost per chair....80$
Friend's chairs..................3
Total chairs..........> cc
cc = 320$/80$ +3
cc = 4 + 3 = 7 chairs
Answer:
Step-by-step explanation:
π/2 < 4π/5 < π
4π/5 is in Quadrant II
sin(4π/5) = y-coordinate of A
Answer:
below
Step-by-step explanation:
area to be repaired = 24*15=360ft^2
1 bag = 2ft^2
? 360ft^2
360/2 = 180 bags needed
cost of bags = 180*24.95=4491$
Answer:
Stefanie bought 10 erasers
Step-by-step explanation:
We can establish the following equation:
TP = NP*PP + NE*EP
Where:
TP = Total price; (4.25)
NP = Number of pencil packages; (1)
PP = Pencil Package's Price; (1.75)
NE = Number of erasers; (What we are looking for)
EP = Erasers Price; (0.25);
Then:
4.25 = 1*1.75 + NE*0.25;
4.25 - 1.75 = NE*0.25;
2.5/0.25 = NE;
10 = NE.
Answer:
Given: circle
diameter = 10 cm => radius (R) = 5 cm
Find: measure of angle bounding sector = 11 π sq. cm.
Plan: determine what part of the circle’s total area equals the sector’s area.
Total Area of Circle A = π R^2 = π 5^2 = 25 π sq. cm.
Therefore: Sector Area = 11 π cm^2/25 π cm^2 = 11/25
Since the sector is 11/25 th of the circles area, the sector angle will measure 11/25 th of the circle’s circumference. They are proportional.
C = 2 π R = 2 π (5) = 10 π cm
Sector Arc = measure of sector angle = 11/25 (10 π) =
22π/5 radians
Answer: Sector Arc = 22π/5 Radians
